Suppose now that you have good arguments to say that the association between X and C (the unobserved confounding factor, here IQ at age 3), measured by γCX, is of a similar magnitude as the association between X and A, measured by γAX — which you can compute in your data (since A is observed). Would this new condition (γCX = γAX). Why?
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Suppose now that you have good arguments to say that the association between X and
C (the unobserved confounding factor, here IQ at age 3), measured by γCX, is of a similar
magnitude as the association between X and A, measured by γAX — which you can compute
in your data (since A is observed). Would this new condition (γCX = γAX). Why?
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- The gama hat for the association between job satisfaction and happiness is 0.40. Does the gamma hat of 0.22 represent a stronger or weaker association than the gamma hat of 0.40?1. Gravetter/Wallnau/Forzano, Essentials - Chapter 5 - End of Chapter question 25 For each of the following, identify the exam score that should lead to the better grade. A score of X = 60 on an exam with µ = 72 and σ = 12, or a score of X = 70 on an exam with µ = 82 and σ = 8? X = 60 corresponds to z = , and X = 70 corresponds to z = . Therefore,both scores produce the same grade . A score of X = 85 on an exam with µ = 70 and σ = 10, or a score of X = 58 on an exam with µ = 49 and σ = 6? X = 85 corresponds to z = , and X = 58 corresponds to z = . Therefore,the better grade would be X = 85, µ = 70, σ = 10 . A score of X = 32 on an exam with µ = 24 and σ = 4, or a score of X = 26 on an exam with µ = 20 and σ = 2? X = 32 corresponds to z = , and X = 26 corresponds to z = . Therefore,the better grade would be X = 26, µ = 20, σ = 2 .The Office of the University Registrar of Seoul University would like to know if the degree programs in College of Science and Math are equally preferred by students. Furthermore, the office would like to know if such degree programs are related to the gender of the students. The test claim that the proportions of the students enrolled are equal in each degree program at alpha=0.05 Using the data on the number of currently enrolled students in each gender (M of F) in each of the four degree programs, find the: a. Table showing the observed and expected values b. Chi-square critical Value c. Chi-square test statistic d. Accept or Reject the null hypothesis?
- The management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.005, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the Zoo Elephants Lions/Tigers Giraffes Zebras Monkeys Birds ReptilesNumber of visitors 152 175 185 144 145 171 163 Step 2 of 4 : Calculate the expected value for the number of visitors for the birds exhibit. Enter your answer as a fraction or a decimal rounded to three decimal places. Step 3 of 4: Compute the value of the test statistic. Round any calculations to at least six decimals places and round your final answer to three…A random sample of 80 poultry farms of one variety gave an average production of 240 eggs per bird. Another random sample of 50 poultry farms of another variety gave an average production of 195 eggs per bird. At a=0.05 is there sufficient evidence to support that there is a significant difference between the egg production of the two varieties of birds. Assume o1 =18 eggs and o2=15 eggsThe management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.05, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the ZooElephants Lions/Tigers Giraffes Zebras Monkeys Birds ReptilesNumber of visitors 137 129 161 147 160 134 131 Step 3 of 4 : Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places. Step 4 of 4: Draw a conclusion and interpret the decision. (Reject or fail to reject, Is there enough evidence or not?)
- The management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.05, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the Zoo Elephants Lions/Tigers Giraffes Zebras Monkeys Birds Reptiles Number of visitors 139 136 169 125 174 137 174 Copy Data Step 3 of 4 : Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places.A study to compare two insurance companies on length of stay for pediatric asthma patients randomly sampled 393 cases from Insurer A. An independent random sample of 396 cases from Insurer B gave the results on length of stay, and the summary statistics are show below. Insurer A (Group 1): x⎯⎯⎯x¯ = 2.31, ss = 1.22, nn = 393Insurer B (Group 2): x⎯⎯⎯x¯ = 2.96, ss = 1.5, nn = 396 Unless otherwise stated, give your answers to three decimal places. Construct a 99% confidence interval for the difference in average length of stay between Insurer A and Insurer B. Give your answers to three decimal places. Use t∗=2.582t∗=2.582.( , ) Conduct a hypothesis test to determine whether the average length of stay for Insurer A is different from than the average length of stay for Insurer B. What is the parameter of interest?i. ppii. μμiii. p1−p2p1−p2iv. μ1−μ2μ1−μ2v. μdμd What is the correct null value for this test? What sign should appear in the alternative hypothesis?i. == ii.…In a clinical study, a random sample of 540 participants agree to have their blood drawn, which is to be examined for the presence of antibodies against a certain contagious disease. It is found in 22% of the blood samples, which experimenters hope to extrapolate to the general population. From this random sample, 10 participants' blood samples are selected at random. If X is the number of samples out of the 10 who have these antibodies, what can we say about X? A. The sample size is not large enough for us to approximate X using a normal distribution B.The expected value of X is 22 C. X can be approximated using a normal distribution in lieu of a binomial distribution D. X has a sampling distribution that is normal
- . A survey was conducted in respect of marital status and success in examination. Out of 2,000 persons who appeared for an examination, 80% of them were boys, and the rest were girls. Among 300 married boys 140 were successful. 1100 boys were successful among unmarried boys. In respect of 100 married girls 40 were successful, 200 unmarried girls were successful. Construct two separate nine-square tables, and find out the Yule's Coefficient of Association to discuss the association between marita! and passing of examination,When the health dept. tested private wells in a county for 2 impurities commonly found in drinking water, it found that 20% of the wells had neither impurity, 30% had impurity A, 40% had impurity B, and 10% had both impurities. If 20 wells are randomly inspected from those in the county, find the prob. that 10 had neither impurity, 4 had impurity A, 4 had impurity B,and 2 had both impurities (rounded odd to 4 decimal places).. A. 0.0001 B. 0.1011 C. 0.2900 D. 0.9990An SRS of 100 flights by Speedy Airlines showed that 64 were on time. An SRS of 100 flights by Happy Airlines showed that 80 were on time. Let pS be the proportion of on-time flights for all Speedy Airline flights, and let pH be the proportion of all on-time flights for all Happy Airlines flights. Is there evidence of a difference in the on-time rate for the two airlines? To determine this, you test the hypotheses H0 : pS – pH 0, Ha : pS – pH 0. The P-value of your test is 0.0117. Which of the following is an appropriate interpretation of the P-value? a. If the on-time rates for the two airlines are equal, there is a 0.0117 probability of getting samples with a difference as far or farther from zero as these samples. b. If the on-time rates for the two airlines are not equal, the probability of getting samples with a difference as far or farther from zero as these samples is 0.9883. c. The probability of making a Type I error is 0.0117. d. The probability of making a Type II error…