Suppose that in Sample Problem 7.7, the orientation of the second and third filters are interchanged. Find the intensity of light emerging from each filter. Polarized light may also be produced at a particular angle of incidence called Brewster's angle or polarizing angle. At Brewster's angle, the reflected ray is almost completely polarized and is perpendicular to the refracted ray (figure 7-13). Using Snell's law and taking 90° 82 N1 = Nair=1.00 and n2=n (of the reflecting surface), the Brewster's angle is given by Fig. 7-12. At the polarizing angle 0, the reflected and refracted rays are perpendicular to each other. tan 0,=n. Eq. (7.14)

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Chapter37: Diffraction Patterns And Polarization
Section: Chapter Questions
Problem 32P: An unpolarized beam of light is incident on a stack of ideal polarizing filters. The axis of the...
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PLEASE ANSWER 7.7 PRACTICE EXERCISE IN GRECA METHOD WAY
that the axes of transmission of the second and third
Three polarizing filters are arranged in such a way
Assuming that the first polarizer is an ideal polarizer,
filters are 30° and 75° to that of the first, respectively.
find the intensity of light emerging from each filter if
Sample Problem 7.7
130°
6=12 W/m?
irs original intensity is 12 W/m²
Given: 62=30°
O3 =75°-30°=45°
I,=12 W/m?
Solution:
1. after passing through the first filter =
(12 W/m?)
= 6 W/m
2
1. after passing through the second filter =
max Cos o = 1, cos¢, = (6 W/m²)cos² 30° = 4.5 W/m´
1. after passing through the third filter = I cos²6 = I, cos'd, = (4.5 W/m²) cos 45°=2.25 W/m*
max
Practice Exercise 7.7
Suppose that in Sample Problem 7.7, the orientation of the second and third filters are
interchanged. Find the intensity of light emerging from each filter.
Polarized light may also be produced at a particular angle of
incidence called Brewster's angle or polarizing angle. At Brewster's angle,
the reflected ray is almost completely polarized and is perpendicular
to the refracted ray (figure 7-13). Using Snell's law and taking
n = Nair=1.00 and n,=n (of the reflecting surface), the Brewster's angle
is given by
90°
82
Fig. 7-12. At the polarizing angle
Eq. (7.14) Op, the reflected and refracted rays
are perpendicular to each other.
tan O,=
=n.
....------
Transcribed Image Text:that the axes of transmission of the second and third Three polarizing filters are arranged in such a way Assuming that the first polarizer is an ideal polarizer, filters are 30° and 75° to that of the first, respectively. find the intensity of light emerging from each filter if Sample Problem 7.7 130° 6=12 W/m? irs original intensity is 12 W/m² Given: 62=30° O3 =75°-30°=45° I,=12 W/m? Solution: 1. after passing through the first filter = (12 W/m?) = 6 W/m 2 1. after passing through the second filter = max Cos o = 1, cos¢, = (6 W/m²)cos² 30° = 4.5 W/m´ 1. after passing through the third filter = I cos²6 = I, cos'd, = (4.5 W/m²) cos 45°=2.25 W/m* max Practice Exercise 7.7 Suppose that in Sample Problem 7.7, the orientation of the second and third filters are interchanged. Find the intensity of light emerging from each filter. Polarized light may also be produced at a particular angle of incidence called Brewster's angle or polarizing angle. At Brewster's angle, the reflected ray is almost completely polarized and is perpendicular to the refracted ray (figure 7-13). Using Snell's law and taking n = Nair=1.00 and n,=n (of the reflecting surface), the Brewster's angle is given by 90° 82 Fig. 7-12. At the polarizing angle Eq. (7.14) Op, the reflected and refracted rays are perpendicular to each other. tan O,= =n. ....------
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