Suppose the car in the previous question tries to complete the turn with tires that provide a coefficient of friction of 2.1 between the tires and the level road surface. What is the maximum speed of the car as it successfully turns?   Previous Question: 4. The driver of a 1300kg car wants to turn a corner of radius 57m at a speed of 12m/s. (a) What is the required centripetal force? (b) What is the necessary coefficient of friction to provide this force?

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A: centripetal force F = mv2r

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A: It is given that, l=20 mi=32186.9 md=3.53 mir=d2=3.532=1.765 mi=2840.4922 m

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A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

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A: Centripetal force =mv2R

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Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.