Suppose the molecule below is in basic aqueous solution. Is keto-enol tautomerization possible? If a keto-enol tautomerization is possible, draw the mechanism for it. Be sure any extra reagents you add to the left-hand side of the first step are readily available in this solution. If a keto-enol tautomerization is not possible, check the box under the drawing area.
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- Draw a step-wise mechanism for the following substitution reaction. Be sure to add lone pairs and charges where relevant. CH,OH Br 3Draw reaction mechanisms with all reactants, arrows, intermediates, and products. Your mechanism must account for all the products if more than one product is formed. 4-methycyclohexanol with phosphoric acid H3PO4 to for 1-methycyclohexene, 3- methylcyclohexene and 4-methycyclohexeneSelect the reagents that will allow the following transformation(s) to occur. -H ? 1) NaOH 2) propyl bromide 1) Na2HSO4 2) propylanol 1) NaOH 2) propyl bromide 1) NaNH₂ 2) propyl bromide
- Complete the following keto-enol tautomerizations. Which of these (I, II, III) is expected to have the highest percentage of enol tautomer at equilibrium? You may assume the nitrogen is non-reactive in the tautomerization. I II IIBr CH3OH + Br-Br H3CO The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve a negatively charged nucleophile, the attack of the nucleophile leads directly to the product. +Br + CH3OH Br Intermediate 1 Intermediate 2 (product) In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OH + Br2 + HBr Br racemic mixture • Pay attention to the reactants, they may differ from the examples. In some reactions, one part of the molecule acts as the nucleophile. • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate intermediate 1 and intermediate 2 using the → symbol from the dropdown menu.4. Draw the organic products of the reactions of (R)-2-iodobutane with azide ion and methanol. Draw allstereoisomers expected to form. (R)-2-iodobutane Na*N3* CH3OH
- Three reactions between a Grignard reagent and a carbonyl compound are given. Draw the main organic product for each reaction and indicate if H+ or H¯ is needed to complete each reaction. The starting material structures are provided in the answer fields as a starting point for your drawings. The first reaction involves a ketone. 1. CH₂MgBr 2. H+ or H™? Select Draw / |||||| C Rings O More EraseSuppose the molecule below is in acidic aqueous solution. Is keto-enol tautomerization possible? If a keto-enol tautomerization is possible, draw the mechanism for it. Be sure any extra reagents you add to the left- hand side of the first step are readily available in this solution. If a keto-enol tautomerization is not possible, check the box under the drawing area. 0 OH No keto-enol tautomerization will happen. X Add/Remove step ↑ G X S Click and drag to start drawing a structure.Answer the following questions about curcumin, a yellow pigment isolated from turmeric, a tropical perennial in the ginger family and a principal ingredient in curry powder.a.In Chapter 11, we learned that most enols, compounds that contain a hydroxy group bonded to a C=C, are unstable and tautomerize to carbonyl groups. Draw the keto form of the enol of curcumin, and explain why the enol is more stable than many other enols. b.Explain why the enol O—H proton is more acidic than an alcohol O—H proton. c. Why is curcumin colored? d.Explain why curcumin is an antioxidant.
- Rearrangements can occur during the dehydration of 1° alcohols even though no 1° carbocation is formed—that is, a 1,2-shift occurs as the C − OH2+ bond is broken, forming a more stable 2° or 3° carbocation, as shown. Using this information, draw a stepwise mechanism that shows how CH3CH2CH2CH2OH is dehydrated with H2SO4 to form a mixture of CH3CH2CH = CH2 and the cis and trans isomers of CH3CH = CHCH3. We will see another example of this type of rearrangement in Section 18.5C.uo 9:0A Asiacell I. 02:48 المتبقي متعد د الخيارات Which alkyl halide would react the fastest under substitution conditions with HO-? 2-bromo-2-methylpentane O 2-bromo-3-methylpentane 1-bromo-2,2-dimethylpentane 2-bromopentane 1-bromo-4-methylpentane O 1 of 5#16c. Provide the missing reactants, reagents, or products for the following reaction sequences below.