Asked May 2, 2019

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Suppose the random variable x has a normal distribution with μ = 300 and σ = 30, Find the
value of r that represents the 10th percentile

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Suppose the random variable x has a normal distribution with μ = 300 and σ = 30, Find the value of r that represents the 10th percentile

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Step 1

It is provided that X follows normal distribution with mean = 300 and standard deviation = 30.

Let ‘x’ be the value that represents 10th percentile.

So, it can be written as, P (X < x) = 10% = 0.10.

Step 2

The required value can be calculated by standardizing the X...


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