Suppose you wish to estimate the average height of adults using a sample of 20 adults where the mean is 67 inches and the standard deviation is 4 inches. Calcul confidence interval for the population mean, assuming that the sample was drawn from a normal population. O (65.454 , 68.546 ) (65.128 , 68.872) O (64.441 , 69.559) O (64.887 , 69.123)

Q: (b) Estimate the sample size needed if no estimate of p is available. A sample of elementary school…

A: From the provided information, Confidence level = 95% Margin of error = 0.06

Q: Suppose, according to a 1990 demographic report, the average U. S. household spends $90 per day.…

A: Sample mean = $84.5.Sample standard deviation, s is $14.5.The sample size, n is 30.

Q: A sample of 49 managers reveals a sample mean of $45,420. The standard deviation of the samp is…

A: As the population standard deviation is not known, we will use t-distribution. The number of degrees…

Q: If a sample of 25 fish from my pond has mean weight 157 grams with a standard deviation of 8.3 grams…

A: Given: σ = 8.3 grams  n = 25

Q: Suppose you take a sample of size 45 from a Normal distribution with unknown population mean and a…

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Q: In a random sample of nine people, the mean driving distance to work was 25 miles the sample…

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Q: In the course of designing theater seats, the sitting heights (in mm) of a simple random sample of…

A: Given information: Total number of adult women(n) is 12. Meanx¯ of height of 12 women is 834 mm.…

Q: The 2008 General Social Survey asked, “What do you think is the ideal number of children for a…

A: Given that,  n=678x¯=3.22s=1.99 The point estimate of the population mean is sample mean. That is,…

Q: The local police department attempted to estimate average vehicle speeds along a strip of Main…

A: Standard error- is the standard deviation of its sampling distribution or an estimate of that…

Q: In a study of the lifetimes of electronic components, a random sample of 400 components are tested…

A: Note: Hey, since multiple subparts are posted, we will answer first three subparts according to our…

Q: The 92 million Americans of age 50 and over control 50 percent of all discretionaryincome. AARP…

A: a. It is given that the sample mean is $1873 and the sample standard deviation is $550. The sample…

Q: 2. A marketing research company desires to know the mean consumption of milk per week among males…

A: Solution (2) The provided information are: Margin of error (E) = = 0.08 Confidence level = 80%…

Q: In a random sample of 20 ​people, the mean commute time to work was 31.5 minutes and the standard…

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Q: r. James Lynch conducts a study to find that the average time eople wait in line before they can…

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Q: A weekly tabloid reported that the average income of its subscribers is $39,100. Assume this…

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Q: Based on this output, what are the sample mean income and standard error of the mean income –…

A: By the given output, we can observe that Mean=$79189.87 Standard error of sample mean=$1663.489…

Q: A pizza shop owner wishes to find the 99% confidence interval of the true mean cost of a large plain…

A: Given σ=0.14E=0.11n=?The z-value at 99% confidence is 2.58

Q: What sample size would be needed to estimate the average body temperature of humans if you wished to…

A: Given data,E=0.1z-value at 99% confidence is Zc=2.576σ=0.6n=?

Q: When preparing a national standardized test to be given to sixth graders, The Standard Test Company…

A: We have given that  Sample size n = 50 Sample mean = 135  Standard deviation = 20 95% confidence…

Q: A research firm conducted a survey to determine the mean amount smokers spend on cigarettes during a…

A: Solution

Q: Construct a 95% confidence interval for the true average monthly claim for travelling expenses made…

A: Given Data : sample size = 19 salespeople average monthly expenses claim made by a  was , x¯= R3 500…

Q: A bank officer wants to determine the amount of the average total monthly deposits per customer at…

A: Given,   Margin of error = 200 Standard deviation = 1000   Critical value: Using z-table, the…

Q: A nutritionist is interested in monitoring the calorie intake of women. It was found that in a…

A: Given that  A nutritionist is interested in monitoring the calorie intake of women. Sample size (n)…

Q: Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal…

A: Construction of the test statisticXi~Nμ , O2 , i =cn , independently⇒ x  ~N μ σ2n n-1S2σ2 ~ Xn-12…

Q: A random sample of 10 employees of a company was selected to estimate the mean one-way commute time…

A: Given Information :  A random sample of 10 employees of a company was selected to estimate the mean…

Q: In a random sample of six ​people, the mean driving distance to work was 23.2 miles and the standard…

A: We have given that  Sample size n =6 Sample mean = 23.2 Standard deviation =6.4

Q: Suppose you wish to estimate the average height of adults using a sample of 20 adults where the mean…

A:

Q: A bread shop owner wishes to find the 95% confidence interval of the true mean cost of special…

A: The formula for the sample size needed to estimate a population mean is

Q: The sample size needed to estimate a population mean within 2 units with a 95% confidence when the…

A: Given,σ=8E=2Zc at 95% confidence is Zc=1.96n=?

Q: Suppose that the amount of time teenagers spend playing computer games per week is normally…

A:

Q: In a study, it was estimated that the average annual expenditure on take-outwas Php 75000 for…

A: The 95% confidence interval for the population mean amount spent on take-aways, will signify that,…

Q: 2.The administration at a college wishes to estimate, the proportion of all its entering freshmen…

A: Given;margin of error(E) = 4population standard deviation(σ)= 1.3for confidence level 95%,…

Q: Suppose a random sample of 48 apartments in Toronto was selected and their square footage were…

A: Introduction: A histogram for the apartment sizes in a sample of 48 apartments is given.

Q: Assume that the population has a normal distribution. Thirty randomly selected students took the…

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Q: 2) Wilson Electronics claims that their new line of Plasma TVs will last for 60, 000 hours. A…

A: Obtain the margin of error for the 95% confidence interval. The formula for the margin of error is,…

Q: The average daily volume of a computer stock in 2011 was μ=35.1 million​ shares, according to a…

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Q: Assume that the heights of adult males (in inches) in the Sultanate of Oman are normally distributed…

A: The mean of the height of the male is 69.72 inches. The standard deviation of the height of the male…

Q: It is desired to estimate the proportion of cannabis users at a university. What is the sample size…

A: Here, CL=0.95 and E=0.10.

Q: A random sample of 16 employees taken from the management level of the company gives a mean monthly…

A: Given that  Sample size = 16 , Mean = 17000 , Standard deviation = 5500

Q: Suppose the scale readings are normally distributed with an unknown mean and standard deviation of…

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Q: A manufacturer produces paper that has a mean iength of 10 inches and a standard deviation of 0.1.…

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Q: A tire manufacturer investigated the tread life of its tires. Samples of 10 tires driven 50,000…

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Q: Compute a 95% confidence interval for the true population mean given the following  10 data that…

A: Given, Sample size = 10 Sample mean = 15.3 Sample standard deviation = 3.5   Since the population…

Q: Suppose you wish to estimate the average height of adults using a sample of 20 adults where the mean…

A:

Q: The 92 million Americans of age 50 and over control 50 percent of all discretionaryincome. AARP…

A: Given: n=80σ=550x=1873 (a) At 95% C.I, the margin of error will be as follows: 95% C.I or 0.95Then,…

Q: A survey of a random sample of 40 actuarial scientists who passed all their exams and are 7. working…

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Q: Suppose that the lengths, in inches, of adult corn snakes are normally distributed with an unknown…

A: Given that the sample size is 38, the sample mean is 53 and the sample standard deviation is 6. The…

Q: In a sample of 100 steel canisters, the mean wall thickness was 8.1 mm with a standard deviation of…

A: