Based on this output, what are the sample mean income and standard error of the mean income – ROUNDED TO THE NEAREST DOLLAR? Suppose you somehow found out that the mean income for the population was in fact $78,000. Based only on the confidence interval that you estimated, to what extent would you find that a reasonable number? Why?
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Based on this output, what are the sample
Suppose you somehow found out that the mean income for the population was in fact $78,000. Based only on the confidence interval that you estimated, to what extent would you find that a reasonable number? Why?
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- A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey of 1,850 recruiters and human resource professionals. The infographic indicated that 52% of the people surveyed had reconsidered a job candidate based on his or her social media profile. Assume that the sample is representative of the population of recruiters and human resource professionals in the United States. Would a 90% confidence interval be wider or narrower than the 95% confidence interval from part (a)? widernarrowerA report summarized a survey of 2,305 working adults. The report indicates that 483 of the working adults surveyed said they were very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years. The sample was selected in a way designed to produce a representative sample of working adults. Construct a 95% confidence interval for the proportion of working adults who are very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years. (Round your answers to three decimal places.)Reseacrch commissioned by AT&T and conducted by Braun Research in 2015 polled 2,067 people in the U.S. aged 16-65 who use their smartphone and drive at least once a day. When asked if they used Facebook while driving, 558 respondents answered "yes". a. What is the point estimate for the proportion of drives who access Facebook while driving? b. What is the margin of error for a 95% confidence interval? c. Construct a confidence interval for proportion of all drivers who take pictures while driving. d. Interpret the interval. e. An independent researcher claims that 30% of drivers use Facebook behind the wheel. Based on the interval, is the claim valid? Explain.
- A report summarized a survey of 2,305 working adults. The report indicates that 471 of the working adults surveyed said they were very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years. The sample was selected in a way designed to produce a representative sample of working adults. Construct a 95% confidence interval for the proportion of working adults who are very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years. (Round your answers to three decimal places.) Interpret the interval. 1. There is a 95% chance that the true proportion of working adults who are very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years falls within this interval. 2. We are 95% confident that the true proportion of working adults who are very concerned that their job will be automated, outsourced, or otherwise made obsolete in the next 5 years falls…Drinking A national health organization, concerned about drinking in middle school students, surveyed 220 randomly selected US 8th-grade students and found that 18 of them had had a drink of alcohol in the past month.(a) Find and interpret a 95% confidence interval for the proportion p of US 8th-grade students who drink alcohol.(b) Give the best estimate for p and give the margin of error for the estimate.Sleep apnea is a disorder in which there are pauses in breathing during sleep. People with this condition must wake up frequently to breathe. The article “Postoperative Complications in Patients With Obstructive Sleep Apnea Syndrome Undergoing Hip or Knee Replacement: A Case-Control Study” (R. Gupta, J. Parvizi, et al., Mayo Clinic Proceedings, 2001:897–905) reported that in a sample of 427 people 65 and over, 104 of them had sleep apnea. a) Find a 95% confidence interval for the proportion of those 65 and over who have sleep apnea. b) Find a 99% confidence interval for the proportion of those 65 and over who have sleep apnea. c) Find the sample size needed for a 95% confidence interval to specify the proportion to within ±0.03. d) Find the sample size needed for a 99% confidence interval to specify the proportion to within ±0.03.
- Merrill Lynch Securities and Health Care Retirement Inc. are two large employers in downtown Toledo, Ohio. They are considering jointly offering child care for their employees. As a part of the feasibility study, they wish to estimate the mean weekly child-care cost of their employees. A sample of 10 employees who use child care reveals the following amounts spent last week: $107 $92 $97 $95 $105 $101 $91 $99 $95 $104 Let these values represent a random sample drawn from a normally distributed population. Find a 90% confidence interval for the mean weekly child-care cost (you don’t have to show your calculations of the necessary sample statistics – use a device for that -- but give their values). Do show your calculation the margin of error and CI. (12)b. Using Emily's sample results, what is the best point estimate of the therapists' success rate? c. Using Emily's sample results, construct a 95% confidence interval estimate of the proportion of correct responses made by touch therapists. d. What do the results suggest about the ability of touch therapists to select the correct hand by sensing energy fields? Draw a conclusion about the ability of touch therapists to select the correct hand by sensing energy fields using the results from the previous step in the context of the problem.Self-Reported and Measured Male Heights As part of the National Health and Nutrition Examination Survey, the Department of Health and Human Services obtained self-reported heights (in.) and measured heights (in.) for males aged 12–16. Listed below are sample results. Construct a 99% confidence interval estimate of the mean difference between reported heights and measured heights. Interpret the resulting confidence interval, and comment on the implications of whether the confidence interval limits contain 0.
- b. Using Emily's sample results, what is the best point estimate of the therapists' success rate? c. Using Emily's sample results, construct a 95% confidence interval estimate of the proportion of correct responses made by touch therapists. d. What do the results suggest about the ability of touch therapists to select the correct hand by sensing energy fields? (Choose one from below) (A.) Since the upper confidence limit is above 0.5, there appears to be evidence that touch therapists can select the correct hand by sensing energy fields. (B.) Since the confidence interval is not entirely above 0.5, there does not appear to be sufficient evidence that touch therapists can select the correct hand by sensing energy fields. (C.) Since the confidence interval is not entirely below 0.5, there appears to be evidence that touch therapists can select the correct hand by sensing energy fields. (D.) Since the lower confidence limit is below 0.5, there does not appear to be sufficient…In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies. They describe ad agency output by finding the shares of dollar billing volume coming from various media categories such as network television, spot television, newspapers, radio, and so forth.a. Suppose that a random sample of 400 U.S. advertising agencies gives an average percentage share of billing volume from network television equal to 7.46 percent, and assume that σ equals 1.42 percent. Calculate a 95 percent confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies.b. Suppose that a random sample of 400 U.S. advertising agencies gives an average percentage share of billing volume from spot television commercials equal to 12.44 percent, and assume that σ equals 1.55 percent. Calculate a 95 percent confidence interval for the mean percentage share of billing volume from spot television commercials…The data below are yields for two different types of corn seed that were used on adjacent plots of land. Assume that the data are simple random samples and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval estimate of the difference between type 1 and type 2 yields. What does the confidence interval suggest about farmer Joe's claim that type 1 seed is better than type 2 seed? Type_1 Type_22047 20181961 19812135 20632445 24492285 21911957 19592112 21481422 1441 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the type 1 seed yield minus the type 2 seed yield. The 95% confident interval is __ <μd< __. (round to two decimal places as needed) What does the confidence interval suggest about farmer Joe's claim that type 1 seed is better than type 2 seed? A. Because the confidence interval includes zero,…