survey of 6,500 van owners found that 23% of the vans are for hire. Find the 99% confidence interval of thee true proportion of vans which are for hir

Q: recent poll, 490 people were asked if they liked dogs, and 45% said they did. Find the margin of…

A: Given that  Sample size n =490 Sample proportion p=45%=0.45

Q: Construct a 95% confidence interval for the true proportion of all employees of Handy Glass Pty who…

A: A sample of 135 employees are considered out of which 75 employees are members of the company's…

Q: Out of 100 people sampled, 56 had kids. Based on this, construct a 99% confidence interval for the…

A:

Q: A newsgroup is interested in constructing a 95% confidence interval for the difference in the…

A:

Q: In a recent poll, 420 people were asked if they liked dogs, and 9% said they did. Find the Margin of…

A: Given: Sample size=n=420,Number of people who liked dogs:x=420×9100=37.8≈38,Significance…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A: Solution: a. Let X be the number of Americans in favor of the initiative and n be the number of…

Q: Out of 400 people sampled, 216 had kids. Based on this, construct a 90% confidence interval for the…

A: From the Standard Normal Table, the value of z* for 90% confidence is 1.645. The sample proportion…

Q: 324 out of a simple random sample of 400 students hated their online math course. a.) Find a 99%…

A: Given that, x=324,n=400 The sample proportion is, Critical values: By using the z-table, the…

Q: Out of 100 people sampled, 15 had kids. Based on this, construct a 95% confidence interval for the…

A: Obtain the 95% confidence interval for the true population proportion of people with kids. The 95%…

Q: uman resources managers, 71% of respondents felt they should hire new staff within the next three…

A: The Upper limit can be calculated as: Upper limit = Point estimate (sample proportion) + Margin of…

Q: Out of 500 people sampled, 375 had kids. Based on this, construct a 99% confidence interval for the…

A: Number of people (n) = 500 Number of people had kids (n) = 375 Find z-critical value:…

Q: In a recent poll, 130 people were asked if they liked dogs, and 24% said they did. Find the margin…

A: Given, Total number of people = 130 Probability that a person likes a dog = 0.24 z value at 99%…

Q: In a recent poll, 290 people were asked if they liked dogs, and 40% said they did. Find the Margin…

A:

Q: In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada. Calculate…

A:

Q: In a sample of 120 adults, 106 had children. Construct a 99% confidence interval for the true…

A: We have given that,  Favorable cases (X) = 106 and sample size     (n) = 120 Then,  We will find the…

Q: In a recent poll, 310 people were asked if they liked dogs, and 40% said they did. Find the Margin…

A: Given data: n = 310p⏞ = 40100=0.40C.I = 99%      =0.99Then, calculate αα = 1-0.99   =0.01Now,…

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: A newsgroup is interested in constructing a 99% confidence interval for the difference in the…

A: Given n1=600 X1=407 n2=538 X2=467

Q: In a recent poll, 300 people were asked if they liked dogs, and 71% said they did. Find the Margin…

A:

Q: A newsgroup is interested in constructing a 90% confidence interval for the difference in the…

A:

Q: In a sample of 320 adults, 288 had children. Construct a 95% confidence interval for the true…

A: Here, the number of adults had children, x is 288 and the sample size, n  is 320. The known values…

Q: in a recent poll, 130 people were asked if they liked dogs, and 46% said they did. Find the Margin…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: n a random sample of 61 professional actors, it was found that 22 were extroverts. Find a 95%…

A: Given: p^= 2261=0.36 to find 95% confidence interval

Q: t poll, 240 people were asked if they liked dogs, and 35% said they did. Find the Margin of Error…

A: Given: n = 240 p^=35%=0.35 The value of z at 95% confidence level is 1.96, which can be obtained by…

Q: Out of 200 people sampled, 140 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data,n=200x=140p=xn=140200=0.70z-value at 90% confidence is Zc=1.645

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: Out of 300 people sampled, 99 had kids. Based on this, construct a 99% confidence interval for the…

A:

Q: In a recent poll, 270 people were asked if they liked dogs, and 29% said they did. Find the Margin…

A:

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A: Let p be the population proportion of all Americans who are in favor of a new Green initiative. The…

Q: Out of 200 people sampled, 122 had kids. Based on this, construct a 90% confidence interval for the…

A: Given that, n = 200 x = 122

Q: recent poll, 250 people were asked if they liked dogs, and 52% said they did. Find the margin of…

A:

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: A newsgroup is interested in constructing a 95% confidence interval for the proportion of all…

A: The sample proportion is, p^=xn=370504=0.7341 The sample proportion of all Americans who favor the…

Q: Out of 500 people sampled, 470 had kids. Based on this, construct a 95% confidence interval for the…

A: The sample size n= 500 The sample proportion is 470/500 = 0.94. The confidence level is 95%. The…

Q: Find a 95% confidence interval for the true population proportion.   In a poll of 1079 college…

A: The value of z at 95% confidence level is 1.96, which can be obtained by using the standard normal…

Q: Out of 400 people sampled, 332 had kids. Based on this, construct a 99% confidence interval for the…

A: Given that, Out of 400 people sampled, 332 had kids.  X = 332 N = 400

Q: In a random sample of 205 people, 160 said that they watched educational television. Find the 99%…

A: given that,possible chances (x)=160size(n)=205

Q: A newsgroup is interested in constructing a 95% confidence interval for the difference in the…

A: a) GivenFor Texansx1=432n1=528p^1=x1n1=432528=0.8182For…

Q: In a sample of 570 adults, 485 had children. Construct a 95% confidence interval for the true…

A: The sample size is 570. The number of successes is 485. We have to construct 95% confidence interval…

Q: A newsgroup is interested in constructing a 90% confidence interval for the difference in the…

A:

Q: In a recent poll, 390 people were asked if they liked dogs, and 83% said they did. Find the Margin…

A: We want to find the margin of error

Q: In a sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a…

A: The distribution of proportion is given by a normal distribution. In the given case the sample…

Q: US Adults, 2439 say they hve contributed to a charity in the past 12 months. Construct the 95%…

A: The value of z at 95% confidence level is 1.96, which can be obtained by using the standard normal…

Q: A newsgroup is interested in constructing a 95% confidence interval for the difference in the…

A: (a)   Obtain the 95% confidence interval for the difference in the proportions of Texans and New…

Q: Out of 500 people sampled, 280 had kids. Based on this, construct a 90% confidence interval for the…

A: Given that n=500

Q: A newsgroup is interested in constructing a 99% confidence interval for the difference in the…

A:

Q: In a recent poll, 570 people were asked if they liked dogs, and 14% said they did. Find the margin…

A: From the Standard Normal Table, the z value for 95% level is 1.96.

Q: A newsgroup is interested in constructing a 90% confidence interval for the difference in the…

A: a). Given, As per z-distribution table, the critical value of z at 90% confidence level is obtained…

Q: A newsgroup is interested in constructing a 95% confidence interval for the proportion of all…

A:

Q: A newsgroup is interested in constructing a 90% confidence interval for the difference in the…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.