Sx v2x +1 dx

Q: 4 dx x²

A: SolutionTo find∫24x3-4x2dxFormula∫xndx=xn+1n+1+C

Q: 2. S V3+ Vã dx

A: Given: I=∫3+x33dx   ...1 Apply the substitution method to solve the given integral. Let,…

Q: dx dx V2x –x²

A:

Q: dx 5) | к (1+х) Vx (1 + х)

A: The integral is ∫dx x1+x Let I=∫dx x1+x Substitute u=x du=12xdxdx=2x du

Q: 2x dx 2. J 25x2+7

A: To determine:

Q: 11. Sx(3x² + 4) dx

A:

Q: Evaluate the integrals

A:

Q: dx V1+4x²

A: Consider the indefinite integral, ∫dx1+4x2 To solve this integral, apply u-substitution. Substitute…

Q: dx Vx+3

A: It is known that ∫xndx=xn+1n+1+C, where C is the integration constant.

Q: dx 3. x' +1

A:

Q: Sx-4/5 dx

A: Given, I=∫x-45dx

Q: dx 3. V25-16x

A:

Q: Sx³ In x dx

A: ∫ x³ ln x dx Let us consider it as ∫ udv  Here u = ln x , dv = x³dx du = (1/x) dx  ∫ dv = ∫ x³dx  v…

Q: (4 dx 2 2X Sxー X-I

A:

Q: S(3 – x) dx 12

A:

Q: Sx (Vx-1) dx

A:

Q: Sx³sin (x²) dx

A: Let's solve given integration.

Q: 7 x'dx 2

A:

Q: 2. S 2vx(x2 – 1) dx

A:

Q: Evaluate the integral.

A: Consider the following integral:…

Q: » Sx(2x – 1)'dx 1)

A: Put 2x-1=t, therefore x=t+12 and 2dx=dt substitute the values in the integral to get:…

Q: S (Vx² + 1) dx 4 2

A:

Q: dx 4 ex

A: To evaluate: I=∫ex2e2x−4ex−1dx Assume, ex=t ⇒exdx=dt

Q: L* Vx3 +1 dx

A:

Q: Sx(4x2 +3) dx

A: ∫x(4x2+3)6 dx Let t=4x2+3 dt=8x dx xdx=dt/8 We substitute the values in the given integral.

Q: V- 2 dx +1)

A:

Q: S(2x3 + x)V2x² + 1 dx

A:

Q: .4 dx 2 Vx2-2

A: Given:        ∫24dxx2-2 Apply trigonometric substitution:    substitute x=2sec u and dx=2 sec u tan…

Q: Sx V(x² – 5) dx 3 2

A: We have to solve the given indefinite integral: ∫x x2-53 dx Solving the integral by using…

Q: Væ – 4/x dx

A:

Q: 3 x'Vx² + 1 dx

A:

Q: dx Vx + 1

A:

Q: 3 dx o v9 – x²

A: We know that,  ∫dxa2-x2=sin-1xa+C ∫03dx9-x2=∫03dx32-x2                    =sin-1x3+C Now applying…

Q: Sx²e* dx = %3D

A: Answer

Q: S₁ dx J2x (J2x +9)

A: To solve the given integral.

Q: 2 | Vxe-*dx хе ах

A:

Q: Sx (x² – 2)14 dx

A: Use algebraic substitution to integrate then simplify.

Q: Evaluate: dx. x*V -3

A: We have to evaluate the given integral. By using the trigonometric function and substitution in it.

Q: 7In(x) dx

A: Asymptote is a line such that the distance between the curve and the line approaches to zero as one…

Q: 1 dx 5х-7

A:

Q: dx 1. S V-x2+ 6x + 3

A:

Q: *²+√** dx x2

A:

Q: @Sxe* dx 2

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: Sx(4x² + 3)°dx

A: Consider ∫x4x2+36dx, Take 4x2+3=u, 8xdx=duxdx=du8 So, ∫x4x2+36dx=∫u6du8

Q: Find S 25xe*dx ii) f 5x*(x5 + 7)19 dx i)

A:

Q: .Sx Vx+1 dx

A: The integration of the integral is x√(x+1).

Q: dx dx 3. x1

A: Given ∫dxx3-dxx

Q: 3. dx V3-x

A:

Q: dx (2X+!) Jx²+x

A: Given,         ∫12x+1x2+xdx