Systolic blood pressure for a group of women is normally distributed, with a mean of 115 and a standard deviation of 12. Find the probability that a woman selected at random has the following blood pressures. (Round your answers to four decimal places.)(a) greater than 135(b) less than 105(c) between 105 and 125 Areas Under the StandardNormal Curve0 Z0The value of A is the area under the standard normal curve between z = 0 and z = z, for z, 2 0. Areas for negative valuesof z, are obtained by symmetry.z.АZ,AZ.AZ.A0.000.00000.430.16640.860.30511.290.40150.010.00400.440.17000.870.30781.300.40320.020.030.040.880.890.00800.450.17360.31061.310.40490.17720.18080.01200.460.31331.320.40660.01600.470.900.31591.330.40820.050.01990.480.18440.910.31861.340.40990.060.02390.490.18790.920.32121.350.41150.070.02790.500.19150.930.32381.360.41310.080.03190.510.19500.940.32641.370.41470.090.03590.520.19850.950.32891.380.41620.03980.04380.100.530.20190.960.33151.390.41770.110.540.20540.970.33401.400.41920.980.33650.42070.42220.120.04780.550.20881.410.130.05170.560.21230.990.33891.420.140.05570.570.21571.000.34131.430.42360.150.05960.580.21901.010.34381.440.42510.06360.06750.160.590.22241.020.34611.450.42651.461.471.481.490.170.600.22571.030.34850.42790.610.620.630.180.07140.22911.040.35080.42920.190.07540.23241.050.35310.43060.200.07930.23571.060.35540.43191.071.080.210.08320.640.23890.35771.500.43320.220.08710.650.24220.35991.510.43450.36211.521.530.230.09100.660.24541.090.43570.240.09480.670.24861.100.36430.43700.250.09870.680.25171.110.36651.540.43820.260.10260.690.25491.120.36861.550.43940.37081.561.570.270.10640.700.25801.130.44060.280.11030.710.26111.140.37290.44180.290.11410.720.26421.150.37491.580.44290.11790.12170.12550.12930.26731.590.44410.44520.44630.300.731.160.37700.37901.601.610.310.740.27041.170.320.750.27341.180.38100.330.760.27641.190.38301.620.44740.44840.44950.45050.45150.45250.45350.45450.340.13310.770.27941.200.38491.630.350.13680.780.28231.210.38691.640.360.14060.790.28521.220.38881.650.370.14430.800.28811.230.39071.660.380.14800.810.29101.240.39251.670.390.15170.820.29391.250.39441.680.400.15540.830.29671.260.39621.690.410.15910.840.29951.270.39801.700.45540.420.16280.850.30231.280.39971.710.4564АР-44

Given : μ = 115 σ = 12 a) PX > 135 = 1 - P X ≤ 135 PX > 135 = 1 - P X-11512 ≤ 135-11512 PX…

Answered: Systolic blood pressure for a group of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Systolic blood pressure for a group of women is normally distributed, with a mean of 115 and a standard deviation of 12. Find the probability that a woman selected at random has the following blood pressures. (Round your answers to four decimal places.)

(a) greater than 135

(b) less than 105

(c) between 105 and 125

Areas Under the Standard
Normal Curve
0 Z0
The value of A is the area under the standard normal curve between z = 0 and z = z, for z, 2 0. Areas for negative values
of z, are obtained by symmetry.
z.
А
Z,
A
Z.
A
Z.
A
0.00
0.0000
0.43
0.1664
0.86
0.3051
1.29
0.4015
0.01
0.0040
0.44
0.1700
0.87
0.3078
1.30
0.4032
0.02
0.03
0.04
0.88
0.89
0.0080
0.45
0.1736
0.3106
1.31
0.4049
0.1772
0.1808
0.0120
0.46
0.3133
1.32
0.4066
0.0160
0.47
0.90
0.3159
1.33
0.4082
0.05
0.0199
0.48
0.1844
0.91
0.3186
1.34
0.4099
0.06
0.0239
0.49
0.1879
0.92
0.3212
1.35
0.4115
0.07
0.0279
0.50
0.1915
0.93
0.3238
1.36
0.4131
0.08
0.0319
0.51
0.1950
0.94
0.3264
1.37
0.4147
0.09
0.0359
0.52
0.1985
0.95
0.3289
1.38
0.4162
0.0398
0.0438
0.10
0.53
0.2019
0.96
0.3315
1.39
0.4177
0.11
0.54
0.2054
0.97
0.3340
1.40
0.4192
0.98
0.3365
0.4207
0.4222
0.12
0.0478
0.55
0.2088
1.41
0.13
0.0517
0.56
0.2123
0.99
0.3389
1.42
0.14
0.0557
0.57
0.2157
1.00
0.3413
1.43
0.4236
0.15
0.0596
0.58
0.2190
1.01
0.3438
1.44
0.4251
0.0636
0.0675
0.16
0.59
0.2224
1.02
0.3461
1.45
0.4265
1.46
1.47
1.48
1.49
0.17
0.60
0.2257
1.03
0.3485
0.4279
0.61
0.62
0.63
0.18
0.0714
0.2291
1.04
0.3508
0.4292
0.19
0.0754
0.2324
1.05
0.3531
0.4306
0.20
0.0793
0.2357
1.06
0.3554
0.4319
1.07
1.08
0.21
0.0832
0.64
0.2389
0.3577
1.50
0.4332
0.22
0.0871
0.65
0.2422
0.3599
1.51
0.4345
0.3621
1.52
1.53
0.23
0.0910
0.66
0.2454
1.09
0.4357
0.24
0.0948
0.67
0.2486
1.10
0.3643
0.4370
0.25
0.0987
0.68
0.2517
1.11
0.3665
1.54
0.4382
0.26
0.1026
0.69
0.2549
1.12
0.3686
1.55
0.4394
0.3708
1.56
1.57
0.27
0.1064
0.70
0.2580
1.13
0.4406
0.28
0.1103
0.71
0.2611
1.14
0.3729
0.4418
0.29
0.1141
0.72
0.2642
1.15
0.3749
1.58
0.4429
0.1179
0.1217
0.1255
0.1293
0.2673
1.59
0.4441
0.4452
0.4463
0.30
0.73
1.16
0.3770
0.3790
1.60
1.61
0.31
0.74
0.2704
1.17
0.32
0.75
0.2734
1.18
0.3810
0.33
0.76
0.2764
1.19
0.3830
1.62
0.4474
0.4484
0.4495
0.4505
0.4515
0.4525
0.4535
0.4545
0.34
0.1331
0.77
0.2794
1.20
0.3849
1.63
0.35
0.1368
0.78
0.2823
1.21
0.3869
1.64
0.36
0.1406
0.79
0.2852
1.22
0.3888
1.65
0.37
0.1443
0.80
0.2881
1.23
0.3907
1.66
0.38
0.1480
0.81
0.2910
1.24
0.3925
1.67
0.39
0.1517
0.82
0.2939
1.25
0.3944
1.68
0.40
0.1554
0.83
0.2967
1.26
0.3962
1.69
0.41
0.1591
0.84
0.2995
1.27
0.3980
1.70
0.4554
0.42
0.1628
0.85
0.3023
1.28
0.3997
1.71
0.4564
АР-44

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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