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t = 100 s if the initial position at t = 0 s is x0 = -25.0m? Justify your answer. What is the object’s accelerati

t = 100 s if the initial position at t = 0 s is x0 = -25.0m? Justify your answer. What is the object’s accelerati

Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section: Chapter Questions
Problem 84A
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From the above plot of velocity versus time, calculate the final position x at
t = 100 s if the initial position at t = 0 s is x0 = -25.0m? Justify your answer.

What is the object’s acceleration at t = 10 s, t = 40 s, and t = 85 s? Justify your answers.

Kinematics in 1D: Velocity vs. Time Graphs 70 Ax = Ax = Ax = Ax = Ax = Ax%D Ax = Ax = 100 m 300 m 200 m 0m 0m 100 m -200m -100 m 200 m 200 m 0 m 0m 60 a= 2 Move the blue dots a= -4 m/s a 2 a = 0 a3D0 a = -2 a = 0 a= 2 a=D 4 a = -4 a = 0 a = 0 to adjust the velocity m/s2 m/s m/s m/s m/s² m/s m/s m/s m/s m/s m/s2 values on the graph. 50 40 30 Velocity (m/s) 20 10 Time (s) 10 20 30 40 60 70 80 90 100 110 120 130 140 -10 Total displacement during time interval of -20 shaded region 600 m Average velocity -30 during time interval At = 120 s of shaded region =5 m/s -40 Move the red dots to change the time interval
Transcribed Image Text:Kinematics in 1D: Velocity vs. Time Graphs 70 Ax = Ax = Ax = Ax = Ax = Ax%D Ax = Ax = 100 m 300 m 200 m 0m 0m 100 m -200m -100 m 200 m 200 m 0 m 0m 60 a= 2 Move the blue dots a= -4 m/s a 2 a = 0 a3D0 a = -2 a = 0 a= 2 a=D 4 a = -4 a = 0 a = 0 to adjust the velocity m/s2 m/s m/s m/s m/s² m/s m/s m/s m/s m/s m/s2 values on the graph. 50 40 30 Velocity (m/s) 20 10 Time (s) 10 20 30 40 60 70 80 90 100 110 120 130 140 -10 Total displacement during time interval of -20 shaded region 600 m Average velocity -30 during time interval At = 120 s of shaded region =5 m/s -40 Move the red dots to change the time interval
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