It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed%3D%3Dbasement with a volume of 2.0 x 103 m3.How many atoms of 222Rn will remain after 24 hours?A. 2.5 x 1018B. 1.0 x 1019C. 8.5 x 1018D. 4.3 x 1020

In this question, we want to determine the number of atom of Rn after 24hr. You can see details…

t is found that 2.0 x 10-5 mol 222R (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed masement with a volume of 2.0 x 103 m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

t is found that 2.0 x 10-5 mol 222R (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed masement with a volume of 2.0 x 103 m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.1QAP

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Question

It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed
%3D
%3D
basement with a volume of 2.0 x 103 m3.
How many atoms of 222Rn will remain after 24 hours?
A. 2.5 x 1018
B. 1.0 x 1019
C. 8.5 x 1018
D. 4.3 x 1020

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