T1 T2 T3 Initial Volume of NaOH (mL) 0.00 3.95 7.95 Final Volume of NaOH (mL) 3.95 7.95 11.65 Volume of NaOH (mL) 3.95 4.00 3.70 Average. volume NaOH (ml) Ex .3 Data Sheet Using dilution Factor in an Acid Base Titration. HCl (aq) + NaOH (aq) NaCl (aq) + H2O (aq) HCl Solution M1 (HCl ) X V1 ( HCl ) = M2 ( HCl ) X V2 ( HCl ) 1.00 mol/L X 4.00 ml = M2 ( HCl ) X 100.0 ml Molarity of diluted HCl Solution M2 = mol / L NaOH Solution 1 - Volume of NaOH needed for dilution V1 = 10.00 ml 2 -Total volume of diluted NaOH V2 = 100.0 ml 3 - Dilution Factor = V2 / V1 =100ml / 10 ml = 4- Volume of HCl used in Titration V HCl = 10.0 ml 5- Moles of HCl = M2 (0.04 mol/L ) x VHCl 0.01 (L) = moles 6-Moles HCl = Moles of NaOH 7- Molarity of diluted NaOH Solution M2 = moles NaOH / V ave (L) = mol/ L 8- M of (Stock ) NaOH Solution M1 = M2 x Dilution Factor = mol / L 9 -Molar mass of NaOH = 40 g/mol 10- Conc of NaOH in g/L = Molar mass of NaOH X M1 (stock NaOH) = g / L T1 T2 T3 Final Volume of NaOH (mL) Initial Volume of NaOH (mL) Volume of Na OH (mL) Avre. volume NaOH (ml)

Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.102E
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T1

T2

T3

Initial Volume of NaOH (mL)

0.00

3.95

7.95

Final Volume of NaOH (mL)

3.95

7.95

11.65

Volume of NaOH (mL)

3.95

4.00

3.70

Average. volume NaOH (ml)

   

Ex .3 Data Sheet                               Using dilution Factor in an Acid Base Titration.

HCl   (aq) + NaOH (aq)                NaCl (aq)   + H2(aq)

HCl Solution        

M1    (HCl )    X   V1     ( HCl )        = M2   ( HCl )          X   V2 ( HCl )          

1.00 mol/L     X     4.00 ml      =       M2   ( HCl )       X     100.0 ml                   

Molarity of diluted   HCl Solution M2 =                                mol / L   

NaOH Solution

1 - Volume of   NaOH needed for dilution V=     10.00   ml

2 -Total volume of diluted NaOH V2   =   100.0   ml

3 - Dilution Factor   = V2 / V1   =100ml / 10 ml    =

4- Volume of HCl used in Titration V HCl = 10.0 ml

5- Moles of HCl   =   M2 (0.04 mol/L ) x VHCl   0.01    (L)   =                                  moles   

6-Moles HCl   = Moles of NaOH   

7- Molarity of   diluted NaOH   Solution M2 =   moles NaOH    / V ave (L) =                   mol/ L                            

8- M of (Stock )   NaOH   Solution M1 = M2   x Dilution Factor   =                       mol / L                                    

9 -Molar mass of NaOH = 40 g/mol

10- Conc of NaOH   in g/L = Molar mass of NaOH X M1 (stock NaOH)   =                      g / L

 

T1

T2

T3

Final Volume of NaOH (mL)

     

Initial Volume of NaOH (mL)

     

Volume of Na OH (mL)

     

Avre. volume NaOH (ml)

   
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