TABLE 1 LINE 1-2 2-3 3-4 4-5 5-1 TABLE 2 LINE 1-2 2-3 3-4 4-5 5-1 FORWARD BEARING S 38° 39' W N 58°56' W N 24°32' E N 68° 45' E S 55° 13' E DIFFERENCE (F/B-B/B) BACKWARD BEARING N 38° 31' E S 60° 07' E S 24° 15' W S 67° 53' W N 54°28′ W STA ADJUSTED BEARINGS FORWARD BACKWARD COMPUTED INTERIOR ANGLE CORRECTION ADJUSTED INTERIOR ANGLE

TABLE 1 LINE 1-2 2-3 3-4 4-5 5-1 TABLE 2 LINE 1-2 2-3 3-4 4-5 5-1 FORWARD BEARING S 38° 39' W N 58°56' W N 24°32' E N 68° 45' E S 55° 13' E DIFFERENCE (F/B-B/B) BACKWARD BEARING N 38° 31' E S 60° 07' E S 24° 15' W S 67° 53' W N 54°28′ W STA ADJUSTED BEARINGS FORWARD BACKWARD COMPUTED INTERIOR ANGLE CORRECTION ADJUSTED INTERIOR ANGLE

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

Situation 3 X - 6 Y - 9 Z - 7
I vll upvote.....Asap plz
a=2 b=5 3xb=15x mm 12xb=60x mm 10xa kN = 20x kN ((3xb)-0,00735)) = (15x- 0,00735) mm
F=1.25N
ASAP c=8 d=4
Hiii plz. Plz A
I need hand written solution onlyd=6 in D=12 i z1= 6 f z2 = 12 f Q= 13 cfsttn
Show complete solution and answer in the nearest 4 decimal places. An engineer's transit is setup at point B which has an elevation of 145.65m above MSL. Point B issituated between points A and C. Point B is the lowest among the three points. The horizontal distance BA and BC are 180m and 200m respectively. The rod reading at A is 1.50m with the line of sight inclined 15 degrees with the horizontal. The rod reading at C is 1.95m with the line of sight inclined 35 degrees with the horizontal. The height of the instrument/transit is 1.10m from the ground. a) What is the difference in elevation of point A and C? b) What is the elevation of point €?
d1 (mm)=16 d2 (mm)=22 P (kN)=55 L (mm)=400
Answer proplem 1,3 and 1.4
skip if you alkeady did this or else downvote
ADDITIONAL INFO: KxLx=17.6, KyLy=10, phiPn of W10x77=869kips, phiPn of W12x53=167kips SHOW STEPS