tan 5x - 1 = 0

Q: Solve for x if 0 ≤ x ≤ 360◦ tan x = −1

A:

Q: (a) sec (40) tan (40) ɖ0

A: We have to solve

Q: sec2 (2x) -d.xp 2. Evalaute tan(2x)

A: Given:

Q: Evaluate ∫tan4 x dx.

A:

Q: | tan 3x sec 3xdx 3.

A:

Q: What is csca if sec a = -4/3 and tana < 0?

A: What is csca if seca=-43 and tana&lt;0?

Q: % D = tan x 27 1+ 2n 2 2 -1

A:

Q: sec (tan-!1+ csc- 1)

A: Givensec(tan-11+csc-11)

Q: 2. sin 4x da =

A: Given query is to find the integral of the expression.

Q: 1. y = (5x - 8)* + Sin(tan2x)

A: Note: Since you have asked multiple question, we will solve the first question for you. If you want…

Q: . tan-1 (- 1) =_____________

A: Given expression: tan-1-1 Consider the value of tan-1-1=x Then, tanx=-1

Q: sec 5x tan 5x dx

A:

Q: sec2 xdx tan? x + 4

A:

Q: sec (2x) dx (tan 2x-4)"

A: We have  ∫sec2(2x)tan2x-43dxLet  tan2x=u    diff. w.r.t x we get2sec2(2x)= dudx sec2(2x)dx=12du now…

Q: SIMPLIFY : TAN (I18 °-2x) + TAN 32°t 2x) |- TAN (l18° -2x) TAN (32° t 2x)

A: Use formula for tan(A+B)

Q: Solve 2 sin x - 1 = 0 for x.

A: Sin of angle is positive for first and second quadrant. And it is negative for third and fourth…

Q: Evaluate integral

A:

Q: Solve: sin -1

A:

Q: tan (x) sec" (x)dæ

A:

Q: tan-1 dx

A: Given data: The given integral is I=∫tan-1xx2dx. The given integral can be evaluated by integration…

Q: tan - de 3 3 sec

A: According to Bartleby's guidelines we can solve only 1 question at a time. Here's the solution for…

Q: tan^2x-2tanx-3/tanx+1

A: First, we have to factor tan^2x - 2tanx-3.

Q: Tan(sin-1(-1/4))=

A: Consider the given expression:

Q: sec (tan"(-5))

A: We have to find the value of expression: sectan-1-13 Let θ=tan-1-13 then tanθ=-13 We know the…

Q: (tan 4x + sec 3x) dx

A: Answer is mentioned below

Q: 14) y = tan (x) b. a. 10- 10- -10- c. 10- 10- 10-

A:

Q: Sketch : 3 sin (x-T/4) +2

A: Start with the standard trigonometric function y = sin(x) and transform it to get the graph…

Q: | tan'x sec'x d.

A:

Q: (cos7x-cos5x)/(cos7+cos5x)=tan6xtanx

A:

Q: tan(0.2x - π)= -9

A:

Q: tan cx)-1 tan (x)-3

A:

Q: tan (3x) sec (2x)

A: We have to solve the problem

Q: Find ∫ tan5 x dx

A: To integrate: ∫tan5xdx.  Given integral can be written as: ∫tan5xdx=∫sin5xcos5xdx Let substitute…

Q: tan(sin-1(4/5))

A: The given expression is

Q: tan(h2x) 2tan(hx) 1+ tan(h²x,

A: It is known that tanh2x=sinh2xcosh2x also sinh2x=2sinhxcoshx and cosh2x=cos2hx+sin2hx Substitute the…

Q: 7. tan (8x) sec (8r) da

A:

Q: 4. tan²B + 1 = sec² B

A:

Q: tan³/3x secº/3x

A: Given that, ∫tan33xsec63xxdx

Q: tan'3xsec"X

A: LetI=∫tan33xsec43xdxI=∫tan23x.tan(3x).sec43xdxWe know…

Q: ∫sec^6 ⁡θ tan^2 ⁡θ dθ

A: Evaluate the given integral as follows. ∫sec6θ tan2θ dθ=∫sec2θsec2θ2 tan2θ dθ=∫sec2θ1+tan2θ2 tan2θ…

Q: į tan 7xdx

A:

Q: y-3x +tan X

A: To Find :  dy/dx  1) d/dx[ tan(x) + 3x] = d/dx[tan(x)] + 3.d/dx [x]

Q: Solve 18xy + sin (2x - y) = 0.

A:

Q: | 3sec" (3x) tan (3x) dx

A:

Q: Ctanx-tan3x tan3x find 1-Ctan2r

A:

Q: | tan 3x sec" 3xdx 5. 12

A: Given: I=∫tan3xsec123xdx For evaluating given integral, we substitute sec3x=t…

Q: y = 3 tan 2x + tan³ 2x

A:

Q: Se -4X Sin h (ex)dr

A:

Q: 2m tan (tan(-))

A: tan -2π3=-tan 2π3=-tan π-π3=--tan π3=tan π3.

Q: tan x -1 X 1+ x?

A: