tan 9x - tan 5x 11. Simplify ī + tan 9xtan 5x

Q: tan (180° - 0) = -tan(0).

A:

Q: | tan 3x sec 3xdx 3.

A:

Q: ) tan X 40 32 X 24 Y

A: Given XZ = 40 XY = 24 ZY = 32

Q: Evaluate using substitution.

A: Evaluate the value of limit using substitution. Substitute the value for x and find out the limit.…

Q: 8. tan(4x) 9. cot (3x-5)

A: SOLUTION:-

Q: sec2@ 10. tan@ - - tan@

A:

Q: V3 tan 30 = - 1

A: tan π/6 = 1/3

Q: tan(0)=31/32

A:

Q: 1/ Solve 2tan² 0 - tan0 -1 = 0 ,0<0<360°.

A:

Q: If tan x = -2.5, then what must be the tan (-x) ?

A:

Q: simplify. 2 tan 15° / 1 − tan2 15°

A: We know the formula,  Tan(A+B) = (tanA + tanB)/(1-tanAtanB) Replacing B with A, Tan2A =…

Q: Evaluate: " sin' (;) 4 .2

A: Evaluate :     ∫0πsin7x2cos4x2dx

Q: Simplify the expression. tan –2x-tan –3x 1+tan -2:x tan –3x tan x tan -3x tan -4x tan -5x

A: Consider  tan-2x -tan-3x1+tan-2x tan-3x

Q: SIMPLIFY : TAN (I18 °-2x) + TAN 32°t 2x) |- TAN (l18° -2x) TAN (32° t 2x)

A: Use formula for tan(A+B)

Q: tan –1 [tan(-)] 6

A: Th expression is given as- tan-1tan-7π6 where θ=7π6 Since, θ lies in IIIrd quadrant, hence it should…

Q: Evaluate integral

A:

Q: Solve: 20 tan² (0²) de a. O b. O c. ✓d. sec(0²) - 0 sec(0²) - 0² tan² (0²) - 0 tan(0²) - 0²

A:

Q: 80. tan²x – cot'x = sec²x – csc²x - %3D

A:

Q: Rewrite sin(x+8π/3) in terms of sin(x) and cos(x) and simplify sin(x+8π/3)=

A: Using Sin(A+B) formula

Q: sec²(110) tan²(110) d0 =

A:

Q: Simplify 2 tan 15 degree  / 1- tan 2 15 degree

A: Identity used: 2tanx1-tan2x=tan2x

Q: tan - de 3 3 sec

A: According to Bartleby's guidelines we can solve only 1 question at a time. Here's the solution for…

Q: Verify the identity. (Simplify at each step.) tan4 x = tan² x sec² x - tan² X tan4 x = (tan² x) = =…

A: I have appended the formula used in the solution part of the question

Q: seë x doX 2 tan 2

A: The given integral can be estimated by substitution method. Let u = tan x. Then,

Q: Tan(20)-tan0=0

A: see 2nd step.

Q: sec (tan"(-5))

A: We have to find the value of expression: sectan-1-13 Let θ=tan-1-13 then tanθ=-13 We know the…

Q: Slmplify. tan 5a+tan æ 1-tan 5¤-tan æ tan 4x tan 6x tan (-6x) tan 11x

A:

Q: tan(0.2x - π)= -9

A:

Q: tan (3x) sec (2x)

A: We have to solve the problem

Q: Simplify the expression sec2⁡x−1/tan⁡x . tan⁡x sec⁡x sec2⁡x tan2⁡x

A:

Q: и Rewrite sin tan -1 as an algebraic expression in U. 3

A: Given,         sintan-1u3

Q: tan 0 = √3 O -60° and -240° O 60° and 240° O 120° and 240° 300° and 240°

A:

Q: Simplify the expression. tan -2a-tan -3 1+tan –2æ tan –3æ tan x tan -4x tan -5x tan -3x

A: tanA-B = tanA-tan(B)1+tan(A)tan(B).

Q: tan-1(tan(6t))

A:

Q: Evaluate. (5x + 5)sin(12)dr

A:

Q: tan(h2x) 2tan(hx) 1+ tan(h²x,

A: It is known that tanh2x=sinh2xcosh2x also sinh2x=2sinhxcoshx and cosh2x=cos2hx+sin2hx Substitute the…

Q: Find the exact value of the expression. + tan- 15 15 tan 1- tan tan- 15 15 |

A:

Q: If sec(x)=-3.6, find sec(-x)

A: Given,         secx=-3.6

Q: Tan(-100) is equal to: Tan 80 Tan 10 -tan 80 -tan 10 Which one?

A: Given query is to find find which is equivalent to tan(-100).

Q: ∫sec^6 ⁡θ tan^2 ⁡θ dθ

A: Evaluate the given integral as follows. ∫sec6θ tan2θ dθ=∫sec2θsec2θ2 tan2θ dθ=∫sec2θ1+tan2θ2 tan2θ…

Q: x = tan 3u

A: Given, x=tan3u

Q: tan(2t) +1 =0

A:

Q: Evaluate tan (8x) sec*(8x) dx.

A:

Q: tan12/1-tan^2 12 simplify

A: Simplify tan121-tan212

Q: do 2 – sin(0)

A: Here we use substitution.

Q: Verify the identity. (Simplify at each step.) tan9 x = tan7 x sec2 x − tan7 x   tan9 x = (tan7…

A: