sec2@ 10. tan@ - - tan@

Q: Hlim X-3 Sinx X->o

A: Given : limx→0x2-3sinxx

Q: (a) sec (40) tan (40) ɖ0

A: We have to solve

Q: eXtan(e*) dx sec²(e*) – 7 2(, - 7

A:

Q: 2 cosx+3 cosx=2, 0Sx<27

A:

Q: | tan 3x sec 3xdx 3.

A:

Q: Find sec 2x -dx. tan 2x cot82x (4sec 22x-1) (A) 12 1 1 I B 12 tan 2x 16 tan 82x Ⓒ -co1²2x-co1³21+ C…

A: Here is the solution

Q: tan (3x)sec (3x) dx

A:

Q: csc (tan 2y-1)dy 5. cos* 2y wil

A: topic - indefinite integral

Q: Sec'x 16-tanx

A: Since you have asked multiple questions in a single request so we will be answering only first…

Q: sec2 () dx x3

A:

Q: ((sec^(2)x-1)(cotx))/(tanxsinx+cosx)

A:

Q: 31T tan 2. (")- sec(-- 4 20n cot(- + csc( 3 8

A:

Q: tan e sec³ e de ' O sec '0 de

A: Consider the given integral as ∫tan3θsec3θdθ

Q: x5tan(x²) sec²(x²) dx

A:

Q: Sec? x cotx-cotx=tanx

A:

Q: sec 5x tan 5x dx

A:

Q: - Sin (x-꼭)+| %3D

A:

Q: tan(-0) sec(-0)

A: " Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: - Se-3x sin 4x dx

A:

Q: 5tan 2x -dx- sin22x-1 8.

A:

Q: Solve sinxtanx=0 if x ϵ [0,2π)

A: Given Equation is sinxtanx=0

Q: Verify please: Tanx(1-cotx)=tanx-1

A: We will use simple trigonometrical ratio to find solution to the problem.

Q: tan (2x)sec (2x)dx 3

A:

Q: tan x sec' x dX

A:

Q: 1 sec @ — tanө %3D sece + tan0

A: rationalizing LHS and using trigonometry formula's to get RHS

Q: Evaluate y” - y’-2y = sin2x

A: Using method of linear differential equation.

Q: (tan 4x + sec 3x) dx

A: Answer is mentioned below

Q: | tan x sec* x dx

A:

Q: COs o + Sin O = Sec0-tan Sec o CSoco

A:

Q: cosx = secx-sinx tanx %3D

A:

Q: ㅠ St tan5 (2x) sec² (2x) dx

A: Given:∫π2πtan5(2x)sec2(2x)dxsubstitute u=tan(2x)differentiate on both sideswe know that…

Q: tan(h2x) 2tan(hx) 1+ tan(h²x,

A: It is known that tanh2x=sinh2xcosh2x also sinh2x=2sinhxcoshx and cosh2x=cos2hx+sin2hx Substitute the…

Q: Differentiate: y = 5 tan? (25x) O y' = 750a? tan(25a³) sec2 (25a) O y' = 7502 tan? (25a) sec(25a*) O…

A:

Q: Differentiate. 3 - sec x y = - tan x y' =

A: Given function: y=3-secxtanx Differentiate the above function w.r.t "x" y'x=ddx3-secxtanx

Q: 2) sec tan 4

A: Solution: The objective is to find the required value

Q: O sec sec 0 – 3 = tan 0 – 4

A:

Q: sec x tan x dx 9+4se ²x 2.

A: We have to evaluate the integral: ∫sec x tan x9+4 sec2 xdx Solving the given integral by…

Q: cos2x+1 CSCX cosx 2 tanx+cotx

A: cos2x+12=cosecx.cosxtanx+cotxL.H.S.=cos2x+12we know that…

Q: Evaluate tan (7x + 1) sec³(7x +1) dx -

A:

Q: 2Cos 2x- Sin20-2

A:

Q: tan 2x sec' n²2x sec 2x dx

A: Evaluate: ∫tan22xsec52xdx

Q: 5. Use 2- step substitution tan 4x sec² (4x) dx

A: To solve the integration

Q: dx sec5x(3+sin5х)

A:

Q: ∫(〖sec〗^2 xdx)/(1+tanx)

A: Given: ∫sec2xdx1+tanx

Q: tan2(x) sec2(x) dx

A: Given,

Q: sec² (x) tan° (x)dx

A:

Q: Find ∫sec4 3x tan3 3x dx.

A: ∫xndx=xn+1n+1+C

Q: tan x sec xdx %3D

A:

Q: Cos2(60°)+sec2(150°)-csc2(210°)

A: To find:

Q: 6- y = (sec(2x) + tan(3x))-2

A: We have given function-  y = [sec(2x) + tan(3x) ]^-2