Task 3: The sketched overhead crane carries the effective force F1 = 60 KN and the balancing load F2 =96 kN on its jib. The weight of the crane bridge is FG1 = 97 kN, the weight of the jib with jib FG2 = 40 KN.The line with a distance 12 from the edge lies exactly in the middle between A and B.Given:1411 = 11.2m= 1.3m12 = 2.2m15= 4.2m113 = 5.6m16 = 0.4mAB-DFG1V13FG2FV62EV16153.1: What is the axle force FA of the rotary trolley with a wheelbase (from A to B) of 2.2 m?a) 218.8 kNb) 74.21 kNc) 163.1 KNd) 32.9 kN3.2: What is the axle force FB of the rotary trolley with a wheelbase of 2.2 m?a) 74.21 kNb) 218.8 kNc) 32.9 kNd) 163.1 kN3.3: What is the supporting force FC on the bicycles of the crane bridge?a) 32.9 kNb) 163.1 kNc) 218.8 kNd) 74.21 kN

provide the specific functionality of the PLC program in the image without more contex

Answered: Task 3: The sketched overhead crane…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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5. The figure below represents the anatomy of the lower limb when balanced on your toes and the body weight acts through the tibia. The Achilles Tendon makes an angle (0) of 8° with the vertical and for this foot x1 is 6.2 cm and x2 is 12.3 cm. Calf Muscle Tibia Achilles Tendon Calculate the tension (T) in the Achilles Tendon if a 70 kg man stands on the toes of both feet. Using the values in this example what is the mechanical advantage for this lever and describe what that means in terms of the efficiency of the lever.
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Practice Problem 3: Solve for the resultant force. F = 500 lb 30 45° F= 800 lb
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The body on the 30° incline, shown in the figure below, is acted upon by a force P inclined at 20° with the horizontal. If P is resolved into components parallel and perpendicular to the incline and the value of the parallel component is 150 N, compute the value of the perpendicular component and that of P. P 20⁰ 30°
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Question 2) The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal. Response

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