Implement and call the following C-style function in MIPS assembly code. You do not have to worry about invalid values of n. The min() function int min(int n, int x[]){ int minval; int i; minval = x[0]; for (i=1; i
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- Implement a range function for a dynamic array which returns a new dynamic array that is a subset of the original. input parameters: array - (the array and any related parameters) start - index of the first elementend - index of the last elementInterval - An integer number specifying the incrementation of index This function returns a new dynamic array containing the elements from the start thru the end indices of the original array.All array indexing must be done using pointer arithmetic. For example, given the array: 49 96 99 47 76 29 22 16 30 22 If the start and end positions were 5 and 9 with step 2, return a new dynamic array: 29 16 22 Please use following main to test your function. int main(){int *p = new int[10]{49,96,99,47,76,29,22,16,30,22}; int *q = range(p,10,5,9,2);for(int i=0;i<3;i++) cout<<q[i]<<" "; // print 29 16 22 cout<<endl;delete [] q;q = range(p,10,1,8,3); for(int i=0;i<3;i++)cout<<q[i]<<" "; // print 96 76 16 cout<<endl;…sub : computer science Pls solve asap.i ll upvote.Thank You Convert this C++ function to an ARM 64 function and please check before bc I've been getting ones that don't assemble or get a segmentation fault.void insertionSort(int arr[], int n) { int i, key, j; for (i = 1; i < n; i++) { key = arr[i]; j = i - 1; // Move elements of arr[0..i-1], // that are greater than key, to one // position ahead of their // current position while (j >= 0 && arr[j] > key) { arr[j + 1] = arr[j]; j = j - 1; } arr[j + 1] = key; } }Task 2The aim of this task is to assess your knowledge in implementing simple loops in MIPS and accessing arrays. To simplify the MIPS code, we have used for i in range rather than for item in the_list. size = int(input("Array length: "))the_list = [None] * size for i in range(len(the_list)):the_list[i] = int(input("Enter num: "))if i == 0 or min_item > the_list[i]:min_item = the_list[i] print("The minimum element in this list is " + str(min_item)) in MIPS please
- implement a function for finding the nth Fibonacci number using the MIPS assembly language. Following gives the definition of the Fibonacci Sequence.Let F be the Fibonacci function:F(0) = 0F(1) = 1For n > 1 F(n) = F(n-1) + F(n-2)Example Output of Execution:Enter the sequence number: 6F(6) = 8 A - Loop ImplementationIn a file named FiboLoop.asm, implement the above function using a loop. B - Recursive ImplementationIn a file named FiboRec.asm, implement the above function using a loop.I'm struggling to create 5 histograms for a set of data in Python. Conceptually the code should produce a histogram which gets smoother and closer to a normal curve as the number of values increases in the array. Mine are all plotting on the same graph however and are separated at weird values and I don't know why. They're not curve like at all. For reference, my 5 arrays of values are generated randomly from a normal distribution with a mean of 12, standard deviation of 1, and contain 5, 50, 500, 5000, and 5000000 values respectively.Write an assembly program(in 8086 use emu 8086) which is able to write a given set ofcharacters in an array to another array in reverse order. Forexample; if an array A is [‘c’ ‘e’ ‘n’ ‘g’] then array B must be [‘g’ ‘n’ ‘e’‘c’].P.S. : It is mandatory to use stack and LODSB-STOSBinstructions. You can use a variable to store array length.
- Instruction: Explain the function of the program line by line thoroughly.Program: #include <iostream> using namespace std; //Swap functionvoid swap(int *xp, int *yp){ int temp = *xp; *xp = *yp; *yp = temp;} void selectionSort(int arr[], int n){ int i, j, min_idx; // One by one move boundary of // unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in // unsorted array min_idx = i; for (j = i+1; j < n; j++) if (arr[j] < arr[min_idx]) min_idx = j; // Swap the found minimum element // with the first element if(min_idx!=i) swap(&arr[min_idx], &arr[i]); }} //Function to print an arrayvoid printArray(int arr[], int size){ int i; for (i=0; i < size; i++) cout << arr[i] << " "; cout << endl;} int main(){ int x, n; cout << "Enter number of integers: "; cin >>n; int *arr = new int(n); for (int i = 0; i < n; i++) { cout << " Enter Integer No. " << (i + 1) << ": ";…Write a program to sort the elements in 1D array in descending order and also implement linear search on the same array. Both sorting and searching operations should be done inside user-defined function: "Task". So,for achieving the required functionality,pass,array into the function: Task () from main () using pass by reference/or address approach.Write a program in C language to sort the elements of 1D array in descending order and alsoimplement linear search on the same array. Both sorting and searching operationsshould be done inside one user defined function: “Task”. So, for achieving the requiredfunctionality, pass, array into the function: Task () from main () using Pass by reference/or address approach.
- I'm having a hard time seeing the problem with this buffer overflow problem can someone please elaborate if its secure or not, and if there are any other issues with the implementation in the problem? Someone tries to fix the stack based buffer overflow problem as follows, is it secure now? why? Are there any other issues within the function's implementation below? Explain your reasoning. int bof(char *str, int size) { char *buffer = (char *) malloc(size); strcpy(buffer, str); return 1; }Write a C program that can take an array of length n having positive unique numbers. You are required to do the following tasks Find the highest element of an array using functions. Split the element into two parts where first part contains the next highest element in that array and second part hold the required additive entity to get the first highest value Print that array where the highest value gets splitted into two parts. Sample input: 4 8 6 3 2 Sample output: 4 6 2 6 3 2(THIS IS FOR MINDTAP ON CENGAGE, PLEASE USE THAT. ALTERNATIVE IS DEVC++5.11 BUT HIGHLY RECOMMENDED THAT YOU USE MINDTAP) Instructions Write a C++ program that declares an array alpha of 50 components of type double. Initialize the array so that the first 25 components are equal to the square of the index variable (the position that element will occupy), and the last 25 components are equal to three times the index variable. Output the array so that 10 elements per line are printed. (For the number at index 5, the value would be 25, which is 5 squared. The 25th index would hold a value of 75, which is 3 * 25.) An example of the program output is shown below: