tensile test is performed on metal specimen and it found that a true plastic strain of 0.02 is produced when a true stress of 345 MPa is applied. How much will a specimen of this material elongate when a true stress of 415 MPa is applied if the original length is 500 mm. Assume that the value of 0.22 for strain hardening exponent.

Q: For a bronze alloy, the stress at which plastic deformation begins is 275 MPa and the modulus of…

A: Note:- As per our guidelines we are supposed to answer only one question. Kindly repost other…

Q: It is known that a brass alloy has a yield strength of 275 MPa, a tensile strength of 380 MPa and a…

A:

Q: A cylindrical specimen of brass that has a diameter of 21 mm, a tensile modulus of 122 GPa, and a…

A: Given that ,  Diameter of cylinderD=21mmModulus of elasticityE=122GPaPoission's ratioμ=0.37Tensile…

Q: With a suitable example explain the difference between True stress-strain and Engineering stress-…

A: Dear student,                     According to the guidelines I am allowed to answer only one…

Q: A metal sample on a tension in the test, , a tensile true strain 0.08, and true stress  when the…

A: Given,  ε1=0.08σ1=265 MPaε2=0.27σ2=325 MPa

Q: tensile test is performed to determine the parameters strength constant C and strainrate…

A: The given data are: σ1=140 MPaT=500 °Cε1˙=10 /sε2˙=150 /sσ2=280 MPa

Q: A specimen with cylindrical shape was subjected to tensile test. Please plot the stress vs. strain…

A: Diameter of test specimen, do=11.600 mmLength of test specimen, lo=50.500 mm

Q: An unknown specimen with an initial diameter of 5.25 mm experiences a reduction in diameter to 4.50…

A: Engineering Stress is defined as load acting on the body per unit original cross-sectional area and…

Q: 1. Two thick slabs of 300mm each, the first one is used in cold rolling where u=0.08 while the…

A: Since we are allowed to answer one question at a time. We’ll answer the first question since the…

Q: When an aluminum tensile sample with an initial diameter of 12.827 mm was tested, a maximum load of…

A: Given Data ⇒ Maximum load(F1)=66.72 KN Engineering strainε1=0.4 Engineering strainε2=0.2

Q: A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a…

A:

Q: Find the strain proportions (ɛ1:E2:E3) that existed in a forming process where O3= 0. Also specify…

A: Given data, Stresses are σ1 σ2=σ13 and, σ3=0

Q: Figure below shows a stress-strain diagram. Explain this curve using your own words and define…

A:

Q: (b) Explain why in a stress versus strain curve, the plastic portion of the graph after necking…

A: Stress depends upon load as well as cross sectional area.

Q: In a typical engineering stress-strain diagram, stress keeps on increasing after yield point due to…

A: Stress Strain Curve is a graphical representation of the behaviour of a material when a load or…

Q: If the moduli of rigidity and elasticity of a material are 15,000 ksi and 40,000 ksi, respectively,…

A:

Q: A material has a strength coefficient of 150,000 psi.  At the onset of plastic deformation, the…

A: The general stress-strain curve is shown below: The engineering strain and true strains are related…

Q: A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness…

A: Given data as per question The initial thickness of the sheet =0.5 in Final thickness =0.25 in The…

Q: b. A paper clip is made of wire 0.4 mm in diameter. If the original material from which the wire is…

A: Given data wire dia (dw) = 0.4 mm rod dia (dr) = 20 mm   To calculate engineering strain and true…

Q: The true strain is

A:

Q: I have plotted stress strain curve as shown in attached pictures. I want to know that: What does…

A: Slope of a stress strain will show the Young’s modulus (E). It is the property of the material which…

Q: 1- With the Vickers hardness test a 10 kg load gave for a sample of brass an indentation with…

A: Given: The load, P = 10 kg The mean length of the indentation, d = 0.51 mm

Q: 3) A tensile test is performed to determine the parameters strength constant C and strain- rate…

A:

Q: The strain hardening exponent and the strength coefficient for aluminum is 0.2 and 180 MPa…

A:

Q: A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a…

A:

Q: A material that has the same tensile and compressive true stress strain curves is compressed to a…

A: Given: σt=20 Mpa εt=15%=0.15 To find: Engineering stress and strain

Q: A tensile test is performed on metal specimen and it found that a true plastic strain of 0.02 is…

A: Given, n = 0.22 ∈1=0.02 σ1=345 MPaσ2=415 MPa

Q: then the true stress-true strain relation (stress in MPa) in the plastic deformation range is

A: Correct answer = option (b)

Q: Compare the differences between hot and cold rolled steel in terms of their processing and…

A: COLD Rolled Hot Rolled  done  below recrystallization temperature, done above recrystallisation…

Q: 1) For a certain metal, the strength coefficient= 700 MPa. A tensile specimen of the metal with gage…

A: Given: Strength coefficient (k)=700MPaGauge length (L)=150mmStretched length (L0)=207mm

Q: Define plane stress and plane strain, making clear which, if any, of the stresses are zero in each…

A: Plane stress If a plane is undergoing load and at any point, the normal stress vector is zero (the…

Q: Calculate the yield strength, tensile strength, strain and Young’s Modulus of a cylindrical tensile…

A: for solution refer below images.

Q: When a load is applied to a member, the deformations cause strain energy to be stored in the…

A: Yes, True. When a load is applied to a member, the deformations cause strain energy to be stored in…

Q: In open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling…

A: Given data as per question The initial diameter of disc =200 mm Height of disc =60 mm The final…

Q: A\ Find the toughness for a metal that experiences both elastic and plastic deformation. The modulus…

A:

Q: Example 2 Assume that a material has true stress - true strain curve given by: O = 100,000 ɛ0.5 psi.…

A:

Q: The relation between maximum utilizable values obtained by tension test and pure shear test for…

A: Maximum shear stress theory is primarily applicable for ductile materials. It is required to…

Q: A specimen of steel has a rectangular cross section 20 mm wide and 40 mm thick, a shear modulus of…

A:

Q: Calculate the stress of the cylindrical rod. Compare with data given in Table Q1 which are the…

A: we have to calculate the stress

Q: Stress can be related to strain. Explain by using experimental methods?

A: Internal stresses introduce due to the application of load in the material. The induces stress…

Q: In a bending test for a brittle material, the distance between the supports is 300mm, the cross…

A:

Q: Describe the relationship between stress and strain according to Hook's law?

A: The relationship between stress and strain according to Hook's law

Q: The strength coefficient and strain-hardening exponent of a certain test metal are 750 MPa and…

A: We need to calculate the final diameter of the specimen

Q: Describe ductile fracture and brittle one. what is the difference between them in tensile test…

A: Given: Tensile test specimen To explain: Brittle and Ductile fracture

Q: As the area under the stress-strain curve decreases, the toughness___________

A: It is required to fill the blank

Q: A cylindrical specimen of brass that has a diameter of 15 mm, a tensile modulus of 100 GPa, and a…

A:

Q: 19. Find the maximum force (kN) that a 2.5 mm thick and 50 mm wide nickel strip, having a yield…

A: Answer: A force which is less than 38.75 kN can withstand with no plastic deformation.

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.