Terrier 8.2 9.4 9.8 12.5 8.8 8.8 11.9 10.7 8.3 10.8 weight (lbs) Dashund 8.8 8.9 10.9 7.4 8.4 7.4 6.7 8.5 5.4 6.9 7.3 weight (lbs) Use the sample data shown above to decide whether the mean weight of terriers is different than than the mean weight of daschunds at a = 0.10. Make sure you are looking at ALL the data. 1. The population distribution requirement for this test is: O None since n, and n2 2 30 O None since this is a Z-test O Need a normally distributed population since this is a T-test O Need a normally distributed population since n, and n2 < 30 The hypotheses are: O Ho: 41 S p2; Ha:µ1 > µ2 O Ho:p 2 Pz; Ha:pi < P2 O Ho: 4 2 42; Ha:µ1 < p2 O Ho:pi < Pzi Ha:p > P2 O Ho: 1 O Ho:p = 42; Ha: 41 # µ2 = p2; Ha:pi p2 2. This is a O rightO leftO two tailed test and the distribution used is OZ since both a values are known OT since both a values are not known Z since testing two proportions 00
Terrier 8.2 9.4 9.8 12.5 8.8 8.8 11.9 10.7 8.3 10.8 weight (lbs) Dashund 8.8 8.9 10.9 7.4 8.4 7.4 6.7 8.5 5.4 6.9 7.3 weight (lbs) Use the sample data shown above to decide whether the mean weight of terriers is different than than the mean weight of daschunds at a = 0.10. Make sure you are looking at ALL the data. 1. The population distribution requirement for this test is: O None since n, and n2 2 30 O None since this is a Z-test O Need a normally distributed population since this is a T-test O Need a normally distributed population since n, and n2 < 30 The hypotheses are: O Ho: 41 S p2; Ha:µ1 > µ2 O Ho:p 2 Pz; Ha:pi < P2 O Ho: 4 2 42; Ha:µ1 < p2 O Ho:pi < Pzi Ha:p > P2 O Ho: 1 O Ho:p = 42; Ha: 41 # µ2 = p2; Ha:pi p2 2. This is a O rightO leftO two tailed test and the distribution used is OZ since both a values are known OT since both a values are not known Z since testing two proportions 00
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Transcribed Image Text:• Question 23
>
Terrier
8.2
9.4
9.8
12.5
8.8
8.8
11.9
10.7 8.3
10.8
weight (lbs)
Dashund
8.8
8.9
10.9
7.4 8.4
7.4
6.7
8.5
5.4 6.9 7.3 8
weight (lbs)
Use the sample data shown above to decide whether the mean weight of terriers is different than than the
mean weight of daschunds at a = 0.10.
Make sure you are looking at ALL the data.
1. The population distribution requirement for this test is:
O None sincen, and n2 > 30
O None since this is a Z-test
O Need a normally distributed population since this is a T-test
O Need a normally distributed population since n, and n2 < 30
or
The hypotheses are:
O Ho: µ < p2; Ha:p1 > p2
O Ho:p1 2 p2; Ha:pi < P2
O Ho:µ1 2 P2; Ha: 41 < 42
O Ho:p < pz; Ha:pi > p2
O Ho: µ1 = 42; Ha:p1 # p2
O Ho:p1 = P2; Ha:p # P2
2. This is a O righto leftO two tailed test and the distribution used is
OZ since both a values are known
OT since both a values are not known
Oz since testing two proportions
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Transcribed Image Text:The Degrees of Freedom (use the simple estimate discussed in the notes, not the messy formula) are
09
ON/A; this is a Z-test
O 10
3. The STS (round to 3 decimals) is:
The P-value (round to 4 decimals) is:
4. The decision at a = 0.10 is:
O Do not reject Ho since P > a
O Reject Ho since P < a
O Do not reject Ho since P< a
O Reject Ho since P> a
The conclusion is:
O There is sufficient evidence to conclude that on average, terrier weight is not different than dashund
weight
O There is sufficient evidence to conclude that on average, terrier wieght is different than dashund
weight
O There is insufficient evidence to conclude that on average, terrier weight is not different than
dashund weight
O There is insufficient evidence to conclude that on average, terrier wight is different than dashund
weight
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