The 5.0 kg, uniform, horizontal rod is seen from the side. What is the gravitational torque about its center of gravity? Use g = 10 m/s2. (Clearly draw the free-body diagram with the pivot, force, and r.) 25 cm Answers: 75 cm 12.5 N-m -12.5 N-m 25 N·m -25 N-m 75 N.m -75 N-m 50 N-m -50 N-m 0 none of the above

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Chapter10: Rotational Motion And Angular Momentum
Section: Chapter Questions
Problem 23PE: (a) Calculate the rotational kinetic energy of Earth on its axis. (b) What is the rotational kinetic...
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The 5.0 kg, uniform, horizontal rod is seen from the side. What is the gravitational torque about its center of gravity? Use g = 10 m/s2. (Clearly draw the free-body diagram with the pivot, force, and r.)
25 cm
Answers:
75 cm
12.5 N-m
-12.5 N.m
25 N-m
-25 N·m
75 N-m
-75 N-m
50 N.m
-50 N-m
0
none of the above
Transcribed Image Text:The 5.0 kg, uniform, horizontal rod is seen from the side. What is the gravitational torque about its center of gravity? Use g = 10 m/s2. (Clearly draw the free-body diagram with the pivot, force, and r.) 25 cm Answers: 75 cm 12.5 N-m -12.5 N.m 25 N-m -25 N·m 75 N-m -75 N-m 50 N.m -50 N-m 0 none of the above
The 5.0 kg, uniform, horizontal rod is seen from the side. What is the gravitational torque about its right end? Use g = 10 m/s². (Hint: It means the right end is the pivot - rotational axis. Clearly draw the free-body diagram with the pivot,
force, and r.)
25 cm
Answers:
75 cm
12.5 N-m
-12.5 N.m
25 N-m
-25 N-m
75 N-m
-75 N-m
50 N-m
-50 N-m
0
none of the above
Transcribed Image Text:The 5.0 kg, uniform, horizontal rod is seen from the side. What is the gravitational torque about its right end? Use g = 10 m/s². (Hint: It means the right end is the pivot - rotational axis. Clearly draw the free-body diagram with the pivot, force, and r.) 25 cm Answers: 75 cm 12.5 N-m -12.5 N.m 25 N-m -25 N-m 75 N-m -75 N-m 50 N-m -50 N-m 0 none of the above
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