The acid dissociation constant K, of acetic acid (HCH,Co,) is 1.8 x 10. D. Calculate the pH of a 0.57 M solution of acetic acid. Round your answer to 1 decimal place.
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- Amino acids are an important group of compounds. At low pH, both the carboxylic acid group (CO2H) and the amine group (NHR) are protonated. However, as the pH of the solution increases (say, by adding base), the carboxylic acid proton is removed, usually at a pH between 2 and 3. In a middle range of pHs, therefore, the amine group is protonated, but the carboxylic acid group has lost the proton. (This is called a zwitterion.) At more basic pH values, the amine proton is dissociated. What is the pH of a 0.20 M solution of alanine hydrochloride, [NH3CHCH3CO2H]Cl?A solution is made by diluting 25.0 mL of concentrated HCl (37% by weight; density = 1.19 g/mL) to exactly 500 mL. Calculate the pH of the resulting solution.14. Acetic acid is a weak acid with the formula CH3COOH; the Ka for acetic acid is 1.76 x 10-5 In aqueous solution, acetic acid partially dissociates according to the following reaction: CH3COOH + H2O ⇔ CH3COO- + H3O+ Calculate the pH of the acetic acid solution described below: Volume: 100 mL Concentration: 0.1708 M Since this is a weak acid, you can assume the amount of acid dissociated is << 5% of the total amount of acid present. a 3.26 b 1.77 c 2.76 d 2.00 e 0.77
- A 250 cm3 volumetric flask contains exactly 200,0 cm3 of a 0,025 mol.dm3sulphuric acid solution. Thereafter ten (10) sodium hydroxide pellets, eachof mass 0,1 g are dropped into the flask. After the pellets have dissolvedcompletely, the flask is topped to the 250 cm3 mark with water and thecontents are thoroughly homogenised. Determine the pH of the resultingsolution.A 0.025 M solution of an unknown organic acid has a pH of 3.23. 2.1 By means of a full calculation, determine the value of the ionisation constant of the conjugatebase of this acid..- You may use “HA” to denote the formula of the acid.- You may make certain assumptions to simplify your calculations2.2 A certain amount of the sodium salt of the conjugate base of the acid was added to the system.Will the pH of the resulting solution increase or decrease, compared to the original given value? Explain your answer in a short sentence or two.A chemist takes 8.579 mL of liquid acetic acid, CH₃COOH (molar mass: 60.052 g/mol) with 1.05 g/mL density and mix it with 12.305 g of solid sodium acetate, CH₃COONa (molar mass: 82.0343g/mol) and prepare an aqueous solution of 1.0 L by adding required amount of water. (Acidity constant of CH₃COOH is 1.8x10⁻⁵) a) What is the pH of such solution?b) What would the pH of the solution be if 0.020 mol NaOH added?c) What would the pH of the solution be if 0.15 mol NaOH added to the solution in a?d) What would the pH of the solution be if 0.17 mol NaOH added to the solution in a? e) What would the pH of the solution be if 0.020 mol HCl added to the solution in a? f) What would the pH of the solution be if 0.15 mol HCl added to the solution in a?g) What would the pH of the solution be if 0.17 mol HCl added to the solution in a?
- A chemist takes 8.579 mL of liquid acetic acid, CH₃COOH (molar mass: 60.052 g/mol) with 1.05 g/mL density and mix it with 12.305 g of solid sodium acetate, CH₃COONa (molar mass: 82.0343g/mol) and prepare an aqueous solution of 1.0 L by adding required amount of water. (Acidity constant of CH₃COOH is 1.8x10⁻⁵) a) What is the pH of such solution?. Single line text.At 25oC, a 100mL solution is found to contain 20% by mass acetic acid (CH3COOH). The density of the solution is 1.05g/cm3. If this solution is diluted further to form 700mL, what will be the A) [OH-], B) pH and C) % dissociation of the resulting acetic acid solution? CH3COOH -> H+ + CH3COO- (Kb = 5.56x10-10)A chemist takes 8.579 mL of liquid acetic acid, CH₃COOH (molar mass: 60.052 g/mol) with 1.05 g/mL density and mix it with 12.305 g of solid sodium acetate, CH₃COONa (molar mass: 82.0343g/mol) and prepare an aqueous solution of 1.0 L by adding required amount of water. (Acidity constant of CH₃COOH is 1.8x10⁻⁵) 1) What is the pH of such solution? 2)What would the pH of the solution be if 0.17 mol NaOH added to the solution in 1? 3)What would the pH of the solution be if 0.020 mol HCl added to the solution in 1? 4)What would the pH of the solution be if 0.15 mol HCl added to the solution in 1? 5)What would the pH of the solution be if 0.17 mol HCl added to the solution in 1?
- A chemist takes 8.579 mL of liquid acetic acid, CH₃COOH (molar mass: 60.052 g/mol) with 1.05 g/mL density and mix it with 12.305 g of solid sodium acetate, CH₃COONa (molar mass: 82.0343g/mol) and prepare an aqueous solution of 1.0 L by adding required amount of water. (Acidity constant of CH₃COOH is 1.8x10⁻⁵) 1) What is the pH of such solution? 2)What would the pH of the solution be if 0.020 mol NaOH added? 3)What would the pH of the solution be if 0.15 mol NaOH added to the solution in a? 4)What would the pH of the solution be if 0.17 mol NaOH added to the solution in a? 5)What would the pH of the solution be if 0.020 mol HCl added to the solution in a? 6)What would the pH of the solution be if 0.15 mol HCl added to the solution in a? 7)What would the pH of the solution be if 0.17 mol HCl added to the solution in a?Calculate the pH of a mixture containing 0.23 M HONH2 and 0.44 M HONH3Cl. (Kb = 1.1 × 10–8) What information do we need to calculate the pH? (Choose all letters that apply.) a. 0.23 M HONH2b. 0.44 M HONH3Clc. the major species in the solutiond. pOH = –log[OH–] and 14.00 = pOH + pHe. Kb = 1.1 × 10–8A solution of acetic acid CH3COOH, on a laboratory shelf was of undetermined concentration. If the pH of the solution was found to be 2.68, what was the initial concentration of the acid? Ka=1.7x10-5 Ethanolamine, HOC2H4NH2, is a viscous liquid with an ammonia-like odour used to remove hydrogen sulphide from natural gas. A 0.15 mol dm-3 aqueous solution of ethanolamine has a pH of 11.34. What is kb for ethanolamine? What is the concentration of hydroxide ion in a 0.060 mol dm-3 aqueous solution of methylamine, CH3NH2? What is the pH? Kb=4.4x10-4