The action of dilute nitric acid on copper is represented by the equation: Cu + HNO9-> Cu+HNO3->Cu(NO3)2+H2O+NO a. What mass of copper would be required to react completely with 250.0 g of nitric acid?| b. How many formula units of cupric nitrate would be formed?

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter4: Stoichiometry
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The action of dilute nitric acid on copper is represented by the equation:
Cu + HNO9-> Cu+HNO3->Cu(NO3)2+H2O+NO
a. What mass of copper would be required to react completely with 250.0 g of nitric acid?
b. How many formula units of cupric nitrate would be formed?
Transcribed Image Text:The action of dilute nitric acid on copper is represented by the equation: Cu + HNO9-> Cu+HNO3->Cu(NO3)2+H2O+NO a. What mass of copper would be required to react completely with 250.0 g of nitric acid? b. How many formula units of cupric nitrate would be formed?
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