The altitude of the helicopter at the three different instants is found to be as follows: Time, ti (sec) ti = 0.20 t2 = 0.30 t3 = 0.41 Altitude, hi (ft) hi = 445-98 h2 = 471.85 h3 = 503.46 %3D • Determine the h(t= o.2999s) and h(t= o.3505) • Determine the rate of climb, dh/dt, at t = 0.30 sec using backward, centred, and forward difference formulas for 1t order accuracy. • Determine the acceleration at time at t = 0.30 sec using backward, centred, and forward difference formulas for 1st order accuracy. • Guess what happen to the altitude before o.20s and after o.41s?

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.