The amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.7 minutes. At a randomly selected time, you observe the broadcast for 1 hour and carefully observe that the amount of advertising time is equal to 9 minutes. Calculate the z- score for this amount of advertising time. Oz = -0.37 z = -2.96 z = 0.37 Oz = 2.96
The amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.7 minutes. At a randomly selected time, you observe the broadcast for 1 hour and carefully observe that the amount of advertising time is equal to 9 minutes. Calculate the z- score for this amount of advertising time. Oz = -0.37 z = -2.96 z = 0.37 Oz = 2.96
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 10PPS
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![Calculate the z-score.
The amount of advertising per hour of broadcast time has an average of 17 minutes
and a standard deviation equal to 2.7 minutes.
At a randomly selected time, you observe the broadcast for 1 hour and carefully
observe that the amount of advertising time is equal to 9 minutes. Calculate the z-
score for this amount of advertising time.
z = -0.37
z = -2.96
Oz = 0.37
z = 2.96](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa714d614-78a6-4d97-b2db-18c7cb38b192%2F3e57af4d-4019-4791-ae26-b8e5c26a911f%2F7jrcku8_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the z-score.
The amount of advertising per hour of broadcast time has an average of 17 minutes
and a standard deviation equal to 2.7 minutes.
At a randomly selected time, you observe the broadcast for 1 hour and carefully
observe that the amount of advertising time is equal to 9 minutes. Calculate the z-
score for this amount of advertising time.
z = -0.37
z = -2.96
Oz = 0.37
z = 2.96
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