Question
Asked Nov 16, 2019
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The amount of coffee that people drink per day is normally distributed with a mean of 16 ounces and a standard deviation of 5 ounces. 6 randomly selected people are surveyed. Round all answers to 4 decimal places where possible.

  1. For the 6 people, find the probability that the average coffee consumption is between 14.5 and 16.5 ounces of coffee per day. 
  2. For part d), is the assumption that the distribution is normal necessary? NoYes
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Step 1
  1. Probability that average coffee consumption is between 14.5 and 16.5 ounces of coffee per day:

The probability that average coffee consumption is between 1...

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14.5-16 x- 16.5 16 P(14.5 <x<16.5)= P 5 5 = P(-0.7349 << 0.2449) =P(z <0.2449)-P(z <-0.7349) using EXCEL fomula -0.2312 "NORM.S.DIST (0.2449,TRUE)", P(z0.2449) 0.2312 using EXCEL formula =0.5948 "-NORM.S.DIST (-0.7349,TRUE)" P(-0.7349)= 0.5948 =0.2312-0.5968 =0.3655

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