The astable 555 Timer operates as follows: 1) When the timer is initially turned on, the capacitor C is completely discharged and begins charging through the combined resistance of R1 and R2 (series) and the output is equivalent to the source voltage, Vs. 2) When the voltage on the capacitor C reaches 2/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to go to 0V, causing the capacitor C to discharge through resistor R2 and the output to go to 0V. 3) Once the voltage on the capacitor C falls to 1/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to no longer be 0V, and the capacitor C begins charging through resistors R1 and R2 and setting the output voltage back to the source voltage.NOTE: if the capacitor is initially charged (Vo), the capacitor charging equation becomes: Vc= Vs+(Vo―Vs)e^(-t/(RC)) 4)Steps 2 and 3 are repeated until power is removed from the circuit and the capacitor fully discharges. Find The amount of time that the output of the 555 Timer is high when the circuit is first powered on, The amount of time that the output of the 555 Timer is low during a regular cycle of the output, and the amount of time that the output of the 555 Timer is high during a regular cycle of the output.
The astable 555 Timer operates as follows: 1) When the timer is initially turned on, the capacitor C is completely discharged and begins charging through the combined resistance of R1 and R2 (series) and the output is equivalent to the source voltage, Vs. 2) When the voltage on the capacitor C reaches 2/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to go to 0V, causing the capacitor C to discharge through resistor R2 and the output to go to 0V. 3) Once the voltage on the capacitor C falls to 1/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to no longer be 0V, and the capacitor C begins charging through resistors R1 and R2 and setting the output voltage back to the source voltage.NOTE: if the capacitor is initially charged (Vo), the capacitor charging equation becomes: Vc= Vs+(Vo―Vs)e^(-t/(RC)) 4)Steps 2 and 3 are repeated until power is removed from the circuit and the capacitor fully discharges. Find The amount of time that the output of the 555 Timer is high when the circuit is first powered on, The amount of time that the output of the 555 Timer is low during a regular cycle of the output, and the amount of time that the output of the 555 Timer is high during a regular cycle of the output.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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The astable 555 Timer operates as follows:
1) When the timer is initially turned on, the capacitor C is completely discharged and begins charging through the combined resistance of R1 and R2 (series) and the output is equivalent to the source voltage, Vs.
2) When the voltage on the capacitor C reaches 2/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to go to 0V, causing the capacitor C to discharge through resistor R2 and the output to go to 0V.
3) Once the voltage on the capacitor C falls to 1/3rd of the supply voltage, the internal circuitry of the 555 Timer IC causes the DIS pin to no longer be 0V, and the capacitor C begins charging through resistors R1 and R2 and setting the output voltage back to the source voltage.NOTE: if the capacitor is initially charged (Vo), the capacitor charging equation becomes: Vc= Vs+(Vo―Vs)e^(-t/(RC))
4)Steps 2 and 3 are repeated until power is removed from the circuit and the capacitor fully discharges.
Find The amount of time that the output of the 555 Timer is high when the circuit is first powered on, The amount of time that the output of the 555 Timer is low during a regular cycle of the output, and the amount of time that the output of the 555 Timer is high during a regular cycle of the output.
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