The average bond enthalpy for C-H is 413 kJ mol.413 kJ mol- of energy is required to break a mole of CH into atoms: CH(9) C(g) + H(g), AH =413 kJ molUsing this information, and your answer from Part A, calculate the enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds in benzene. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) HA AH = Value Units

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter7: Chemical Energy
Section: Chapter Questions
Problem 126CP: The standard enthalpies of formation for S(g), F(g), SF4(g), and SF6(g) are +278.8, +79.0, 775, and...
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From part A ∆H°r=5532.1KJ/mol

From part B C6H6(g)->6CH(g)

 

Part C
The average bond enthalpy for C-H is 413 kJ mol. 413 kJ mol of energy is required to break a mole of CH into atoms:
CH(9) C(9) + H(9),
enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds
AH = 413 kJ mol-Using this information, and your answer from Part A, calculate the
in benzene.
Express your answer to four significant figures and include the appropriate units.
• View Available Hint(s)
HA
AH =
Value
Units
Transcribed Image Text:Part C The average bond enthalpy for C-H is 413 kJ mol. 413 kJ mol of energy is required to break a mole of CH into atoms: CH(9) C(9) + H(9), enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds AH = 413 kJ mol-Using this information, and your answer from Part A, calculate the in benzene. Express your answer to four significant figures and include the appropriate units. • View Available Hint(s) HA AH = Value Units
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