The average height of an adult male is 64.8" with a standard deviation of 1.58". Calculate an interval that is symmetric around the mean such that it contains approximately 95% of heights. Assume that height has a normal distribution. 1) (63.22, 66.38) 2) (66.38, 63.22) 3) (64.8, 1.58) 4) (67.96, 61.64) 5) (61.64, 67.96)

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