The balanced equation for the combustion of butane, CaH1o, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CAH10(g) + 13 02(g) -> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 How many mg of water will be produced by the reaction of 2250 mL of oxygen gas in excess butane?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
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The balanced equation for the combustion of butane, CaH10, is shown below. For your convenience, the molar mass of each substance is
shown below their formulas (in purple). Use this information to make the requested calculation:
2 CAH10(g) + 13 02(g) -> 8 C02(g) + 10 H20(1)
58.124
32
44.011
18.016
How many mg of water will be produced by the reaction of 2250 mL of oxygen gas in excess butane?
Transcribed Image Text:The balanced equation for the combustion of butane, CaH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CAH10(g) + 13 02(g) -> 8 C02(g) + 10 H20(1) 58.124 32 44.011 18.016 How many mg of water will be produced by the reaction of 2250 mL of oxygen gas in excess butane?
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