The base of S is a circular disk with radius 6r. Parallel cross-sections perpendicular to the base are isosceles triangles with height 5h and unequal side in the base. (a) Set up an integral for the volume of S. 10h 6г √36r² - x²dx 5h 6r √36r2 - x²dx 6r 10h 36r2-x²dx -6r 6r 10h -6r (36²x²) dr 10h 6r xdx (b) By interpreting the integral as an area, find the volume V of S. V =

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