The battery of a car has been discharged and removed. The car is started using an external battery and jump-start cables. The combined length ofthe cables connecting the terminals to the start-up motor is l = 5.44 m and the cross-sectional area of the cable is A = 9.4 mm². The start motortakes in a current of Im = 210 A . A voltmeter shows Es = 12.62 V as the external battery voltage, when the motor is disconnected. The internalresistance of the battery is assumed to be R₁ = 10 mResistivity for the copper cable is p = 1.678e - 8 mSHFexternalbatteryWhat is the terminal voltage?Et=20*10^-3(+) cable1/2RV1/2R(-) cable-3Your last answer was interpreted as follows: 2010-What is the total resistance of the cables?Re = 9.71*10^-5Ωmotor What is the voltage drop in the cables?Uc = 1VYour last answer was interpreted as follows: 1What is the voltage of the start-up motor?Um = 12.6*10^0VYour last answer was interpreted as follows: 12.6. 10⁰What is the power loss in cables and inside the battery?Pt = 441*10WYour last answer was interpreted as follows: 441.10

Solution: 1. let's find the resistance of the cables: The resistivity of copper is given as…

The battery of a car has been discharged and removed. The car is started using an external battery and jump-start cables. The combined length of the cables connecting the terminals to the start-up motor is l = 5.44 m and the cross-sectional area of the cable is A = 9.4 mm². The start motor takes in a current of Im = 210 A . A voltmeter shows Es = 12.62 V as the external battery voltage, when the motor is disconnected. The internal resistance of the battery is assumed to be R₁ = 10 m Resistivity for the copper cable is p = 1.678e - 8 Nm SA external battery What is the terminal voltage? Et = 20*10^-3 (+) cable 1/2R 1/2R (-) cable V Your last answer was interpreted as follows: 20-10-³ motor

The battery of a car has been discharged and removed. The car is started using an external battery and jump-start cables. The combined length of the cables connecting the terminals to the start-up motor is l = 5.44 m and the cross-sectional area of the cable is A = 9.4 mm². The start motor takes in a current of Im = 210 A . A voltmeter shows Es = 12.62 V as the external battery voltage, when the motor is disconnected. The internal resistance of the battery is assumed to be R₁ = 10 m Resistivity for the copper cable is p = 1.678e - 8 Nm SA external battery What is the terminal voltage? Et = 20*10^-3 (+) cable 1/2R 1/2R (-) cable V Your last answer was interpreted as follows: 20-10-³ motor

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter21: Current And Direct Current Circuits

Section: Chapter Questions

Problem 19P

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