Photo attached
The circle in the figure below has a radius of r and center at C. The distance from A to B is x, the distance from A to D is y, and the length of arc BD is s. Redraw the figure, label it as indicated, and solve the problem. If A 31°, s = 12, and r = 14, find x. (Round your answer to the nearest whole number.) х 3 В х A у
First of all, redraw the figure and put the given values.
AB = x
BC = CD = 14
AD = 100
∠A = 31°
Arc BD = 12
14 в A 31 12 14 100 D
Now using the arc length BD to find ∠C.
ө arc length 2Trx- 360 ө 2T x BCx- 3600 BD BD 360° ө ВС 27T 12 360° 14 = 49.110° ZC49° (rounding upto nearest whole number)
Now find ∠D using the sum of angles of a triangle law in ...
ZA+ZC+ZD = 180° (in aADC 31° 49° D = 180° ZD 180° -31° - 49° =1000
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