1000=R/ ant"ION 10 (Start on a new page.)The circuit below consists of a 6 Q and 15 Q resistor connected in parallel andan unknown resistor R, Iin serles. An ammeter, a high-resistance voltmeter,a closed switch and battery are connected, as shown. The resistance of thebattery and wires can be ignored.R15 QThe total power dissipated in the parallel part of the circuit is 50 W.10.1.1 Define the term power.10.1.2Calculate the effective resistance of the parallel combination.10.1.3Calculate the potential difference across the resistors in paralel.10.1.4Calculate the current through resistor R.

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The circuit below consists of a 6 Q and 15 Q resistor connected in parallel and an unknown resistor R, in serles. An ammeter, a high-resistance voltmeter, a closed switch and battery are connected, as shown. The resistance of the battery and wires can be ignored. V A 15 Q The total power dissipated in the parallel part of the circuit is 50 W. 10.1.1 Define the term power. 10.1.2 Calculate the effective resistance of the parallel combination. 10.1.3 Calculate the potential difference across the resistors in paraliel. 10.1.4 Calculate the current through resistor R.

The circuit below consists of a 6 Q and 15 Q resistor connected in parallel and an unknown resistor R, in serles. An ammeter, a high-resistance voltmeter, a closed switch and battery are connected, as shown. The resistance of the battery and wires can be ignored. V A 15 Q The total power dissipated in the parallel part of the circuit is 50 W. 10.1.1 Define the term power. 10.1.2 Calculate the effective resistance of the parallel combination. 10.1.3 Calculate the potential difference across the resistors in paraliel. 10.1.4 Calculate the current through resistor R.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter23: Series And Parallel Circuits

Section: Chapter Questions

Problem 54A

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