3.the collision.The conservation of the total momentum before and after the collision is expressed by:m2 2 lu = in?u + In luLikewise, the conservation of the total kinetic energy is expressed by:Eatru + a lu = ntu + luThese equations may be solved directly to find v1, v2 when u1, u2 are known:Tu - lu+ InZu + Tuu2mị + m22m1+In-Tu + Tu7n-u + Tuv2(1) 2.41 m/s south, 7.39 m/s north25.30 m/s south, 2.05 m/s north4.85 m/s north, 3.20 m/s south45.10 m/s north, 2.89 m/s south A bumper car of mass 125 kg, moving at 6.30 m/s to the north, collides 100% elastically, head-on, with a second bumpercar of mass 100 kg moving at 3.50 m/s to the south. What are the velocities of the first and second bumper carsrespectively?Note: the following may come in handy here! In these formulas, uj and uz are the velocities of the two cars before thecollision, and v and v, are the velocities after the collision.VIThe conservation of the total momentum before and after the collision is expressed by:m1u1 + m2 U2 = m1v1 + m2v2.Likewise, the conservation of the total kinetic energy is expressed by:m už +mzu = mvf +m.These equations may be solved directly to find v1, v2 when u1, u2 are known:2m2m2U1 +mị + m2mịmị + m22m1m2 – mị-U1 +mị + m2V2m1 + m21-2.41 m/s south, 7.39 m/s northSave for Later

Given that, Mass of first bumper(m1)= 125 kg Mass of second bumper (m2)= 100 kg Velocity of first…

the collision. The conservation of the total momentum before and after the collision is expressed by: m1u1 + m2U2 = m1vi + m2v2. Likewise, the conservation of the total kinetic energy is expressed by: Entru + fa tu = ntru? + n lu Entru + ļa tu? These equations may be solved directly to find v1, v2 when u1, uz are known: - + In. Zu + Tu m2 Tu + Tu · 2m1 + In- Tu + Tu v2 Tu + Tu (1 2.41 m/s south, 7.39 m/s north 2 5.30 m/s south, 2.05 m/s north 3 4.85 m/s north, 3.20 m/s south 4. 5.10 m/s north, 2.89 m/s south

the collision. The conservation of the total momentum before and after the collision is expressed by: m1u1 + m2U2 = m1vi + m2v2. Likewise, the conservation of the total kinetic energy is expressed by: Entru + fa tu = ntru? + n lu Entru + ļa tu? These equations may be solved directly to find v1, v2 when u1, uz are known: - + In. Zu + Tu m2 Tu + Tu · 2m1 + In- Tu + Tu v2 Tu + Tu (1 2.41 m/s south, 7.39 m/s north 2 5.30 m/s south, 2.05 m/s north 3 4.85 m/s north, 3.20 m/s south 4. 5.10 m/s north, 2.89 m/s south

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter9: Momentum And Its Conservation

Section: Chapter Questions

Problem 96A

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