The combustion of C2H5OH is represented by the equation above and the standard entropy and enthalpy changes for the reaction are provided. When the reactants are combined at 25°C, essentially no CO2(g) or H2O(g) is produced after a few hours. Which of the diagrams above could best help explain the low yield of the reaction under these conditions, and why? A.)Diagram 1, because it represents a reaction that is not thermodynamically favorable with ΔG°>0, regardless of its reaction rate. B.)Diagram 1, because it represents a reaction that reaches equilibrium quickly after a very small amount of the reactants is consumed. C.)Diagram 2, because it represents a reaction with a high activation energy barrier for molecules to overcome and a very slow reaction rate, even if it is thermodynamically favorable with G°<0. D.)Diagram 2, because it represents a reaction that is thermodynamically favorable with ΔH°<0, but the products formed are unstable and quickly revert to form reactants.
The combustion of C2H5OH is represented by the equation above and the standard entropy and enthalpy changes for the reaction are provided. When the reactants are combined at 25°C, essentially no CO2(g) or H2O(g) is produced after a few hours. Which of the diagrams above could best help explain the low yield of the reaction under these conditions, and why? A.)Diagram 1, because it represents a reaction that is not thermodynamically favorable with ΔG°>0, regardless of its reaction rate. B.)Diagram 1, because it represents a reaction that reaches equilibrium quickly after a very small amount of the reactants is consumed. C.)Diagram 2, because it represents a reaction with a high activation energy barrier for molecules to overcome and a very slow reaction rate, even if it is thermodynamically favorable with G°<0. D.)Diagram 2, because it represents a reaction that is thermodynamically favorable with ΔH°<0, but the products formed are unstable and quickly revert to form reactants.
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 17E: Would the amount of heat absorbed by the dissolution in Example 5.6 appear greater, lesser, or...
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The combustion of C2H5OH is represented by the equation above and the standard entropy and enthalpy changes for the reaction are provided. When the reactants are combined at 25°C, essentially no CO2(g) or H2O(g) is produced after a few hours. Which of the diagrams above could best help explain the low yield of the reaction under these conditions, and why?
A.)Diagram 1, because it represents a reaction that is not
B.)Diagram 1, because it represents a reaction that reaches equilibrium quickly after a very small amount of the reactants is consumed.
C.)Diagram 2, because it represents a reaction with a high activation energy barrier for molecules to overcome and a very slow reaction rate, even if it is thermodynamically favorable with G°<0.
D.)Diagram 2, because it represents a reaction that is thermodynamically favorable with ΔH°<0, but the products formed are unstable and quickly revert to form reactants.
Transcribed Image Text:C2H;OH(1) + 3 O2(g) → 2 CO2(g) +3 H2O(g)
AS° = +217.7 J/(molm · K)
AH° = -1235 kJ/moln
DIAGRAM 1
DIAGRAM 2
Reactants
Reactants
Products
Products
Reaction Progress
Reaction Progress
Potential Energy
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