Question
Asked Nov 24, 2019
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The combustion of propane may be described by the chemical equation
3 CO2 (g)4 H20(g)
C3H(g)5 2g)
How many grams of O2(g) are needed to completely burn 57.4 g C3H (g)?
mass O2
g O2
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The combustion of propane may be described by the chemical equation 3 CO2 (g)4 H20(g) C3H(g)5 2g) How many grams of O2(g) are needed to completely burn 57.4 g C3H (g)? mass O2 g O2

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Expert Answer

Step 1

Mole is given by,

mass
mole
Molecular mass
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mass mole Molecular mass

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Step 2

The balanced reaction of combustion of propane is,

СН + 50, —зсо)
4Н,о,
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СН + 50, —зсо) 4Н,о,

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Step 3

Molar mass of propane is 44 g/mol and molar mass of oxygen i...

57.4
g-1.305mol
44g
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57.4 g-1.305mol 44g

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