The cross product of the vectors 3i+ 4j – 5k and -i+j-2k is, a) 3i – 11j + 7k b) -3i + 11j+ 7k c) -3i – 11j - 7k d) -3i + 11j- 7k

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Q: -2 -3 a -5-

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Q: Find the angle θ between the vectors a=5i−j−5kand b=2i+j−2k Answer (in radians): θ=?

A: a→ = 5i^ - j^ - 5k^b→ = 2i^ + j^ - 2k^|a| = 52 + 12 + 52 |a| = 51|b| = 22 + 12 +22|b| = 3

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Q: the cross product

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Q: angle between the vectors

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