The current (sense of flow-direction is AB-BC-CD-DA) in the rectangular loop is I2 = 15.0 A. Consider that the the rectangular loop lies in the magnetic field created by a current-carrying conductor which carries a current I = 12.0 A. The dimensions of the rectangular loop are: AB = CD = 0.8 m and AD = BC = 0.30 m. And the separation distance between CD and the current-carrying conductor is 0.50 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. B_ C H 0.50m A D Į

The current (sense of flow-direction is AB-BC-CD-DA) in the rectangular loop is I2 = 15.0 A. Consider that the the rectangular loop lies in the magnetic field created by a current-carrying conductor which carries a current I = 12.0 A. The dimensions of the rectangular loop are: AB = CD = 0.8 m and AD = BC = 0.30 m. And the separation distance between CD and the current-carrying conductor is 0.50 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. B_ C H 0.50m A D Į

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 43P: In Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the...

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