The data below were determined for the reaction shown below. S2082- + 31- (aq) → 28042- + 13 [S2Og²-] Initial Rate 1.4 x 10-5 M/s 2.8 x 10-5 M/s 1.4 x 10-5 M/s Expt. # [I-1 0.060 1 0.038 0.060 0.030 2 0.076 3 0.076 The rate law for this reaction must be: O rate = k[S 20 8 ] rate = k[S 20 8 2-O³ rate = k[l ] rate = k[S 20 8 27²07² %3D rate = k[S 20 8 2-U
The data below were determined for the reaction shown below. S2082- + 31- (aq) → 28042- + 13 [S2Og²-] Initial Rate 1.4 x 10-5 M/s 2.8 x 10-5 M/s 1.4 x 10-5 M/s Expt. # [I-1 0.060 1 0.038 0.060 0.030 2 0.076 3 0.076 The rate law for this reaction must be: O rate = k[S 20 8 ] rate = k[S 20 8 2-O³ rate = k[l ] rate = k[S 20 8 27²07² %3D rate = k[S 20 8 2-U
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 31E: The following data have been determined for the reaction: I+OCIIO+CI 1 2 3 [I] 0.10 0.20 0.30 [OCI]...
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![The data below were determined for the reaction shown below.
S20g?-
+ 31 (aq) → 2SO42- + 13
Initial Rate
1.4 x 10-5 M/s
2.8 x 10-5 M/s
1.4 x 10-5 M/s
Expt. #
[S2Og²-]
1
0.038
0.060
0.076
0.060
3
0.076
0.030
The rate law for this reaction must be:
rate = k[S 20 8 2
rate = k[S 20 8 2- 73
rate = k[l ]
rate = k[S 20 8 21²u7²
O rate = k[S 20 82](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45c039f8-ca7d-4e83-b6c6-738dc37dc4ac%2F13d0abb6-a6a8-4448-aef5-633699f1845a%2Fiio8bcu_processed.png&w=3840&q=75)
Transcribed Image Text:The data below were determined for the reaction shown below.
S20g?-
+ 31 (aq) → 2SO42- + 13
Initial Rate
1.4 x 10-5 M/s
2.8 x 10-5 M/s
1.4 x 10-5 M/s
Expt. #
[S2Og²-]
1
0.038
0.060
0.076
0.060
3
0.076
0.030
The rate law for this reaction must be:
rate = k[S 20 8 2
rate = k[S 20 8 2- 73
rate = k[l ]
rate = k[S 20 8 21²u7²
O rate = k[S 20 82
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