The decomposition of urea, (NH₂)₂CO, in 0.10 M HCI follows the equation (NH₂)₂CO (aq) + 2H+ (aq) + H₂O2NH₂(aq) + CO₂(g) At 65°C, k = 5.84 x 10 min¹ and at 75°C, k = 2.25 x 105 min¹. If this reaction is run at 85°C starting with a urea concentration of 0.0092 M, how many minutes will it take for the urea concentration to drop to 0.0012 M? minutes

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter13: Fundamental Equilibrium Concepts
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Question 7 of 42
The decomposition of urea, (NH₂)₂CO, in 0.10 M HCI follows the equation
(NH₂)₂CO (aq) + 2H+ (aq) + H₂O → 2NH₂*(aq) + CO₂(g)
At 65°C, k = 5.84 x 10 min-¹ and at 75°C, k = 2.25 x 105 min¹. If this reaction is run at 85°C starting with a urea concentration
of 0.0092 M, how many minutes will it take for the urea concentration to drop to 0.0012 M?
minutes
Transcribed Image Text:Question 7 of 42 The decomposition of urea, (NH₂)₂CO, in 0.10 M HCI follows the equation (NH₂)₂CO (aq) + 2H+ (aq) + H₂O → 2NH₂*(aq) + CO₂(g) At 65°C, k = 5.84 x 10 min-¹ and at 75°C, k = 2.25 x 105 min¹. If this reaction is run at 85°C starting with a urea concentration of 0.0092 M, how many minutes will it take for the urea concentration to drop to 0.0012 M? minutes
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