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The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer.

The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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5. The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. Given: Density of water = 0.967 g/mL. Volume of water = 499.8 mL. The mass of water = density x volume = 0.967 x 499.8 = 483.3066 g.Hence moles of water = Mass of water / molar mass of water = 483.306618 = 26.8504 mol approx.Therefore the number of molecules of water is given by, => Number of water molecules = Moles of watr x Avogadro's number=> Number of water molecules = 26.8504 x 6.022 x 1023 = 1.62 x 1025 molecules. The mass of water = density x volume = 0.967 x 499.8 = 483.3066 g.Hence moles of water = Mass of waterMolar mass of water = 483.306618 = 26.8504 mol approx. Therefore the number of molecules of water is given by,=> Number of w ater molecules = Moles of watr x Avogadro's number> Number of water molecules = 26.8504 x 6.022 x 1023 = 1.62 x 1025 molecules. The answer is 1.62 x 1025 water molecules.
Transcribed Image Text:5. The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. Given: Density of water = 0.967 g/mL. Volume of water = 499.8 mL. The mass of water = density x volume = 0.967 x 499.8 = 483.3066 g.Hence moles of water = Mass of water / molar mass of water = 483.306618 = 26.8504 mol approx.Therefore the number of molecules of water is given by, => Number of water molecules = Moles of watr x Avogadro's number=> Number of water molecules = 26.8504 x 6.022 x 1023 = 1.62 x 1025 molecules. The mass of water = density x volume = 0.967 x 499.8 = 483.3066 g.Hence moles of water = Mass of waterMolar mass of water = 483.306618 = 26.8504 mol approx. Therefore the number of molecules of water is given by,=> Number of w ater molecules = Moles of watr x Avogadro's number> Number of water molecules = 26.8504 x 6.022 x 1023 = 1.62 x 1025 molecules. The answer is 1.62 x 1025 water molecules.
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