The derivative of the function y = xe(5+sec(2x)) is: y' = [1+ 2x sec(2x) tan(2x)]e(5+see(2x)) y' = [1+ x sec(2x) tan(2x)Je(5+sec(2x)) the above the above y' = [1- 2x sec(2x) tan(2x)]e(5+sec(2x)) y' = [1-x sec(2x) tan(2x)Je(5+sec(2x)) the above the above

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