The differential equation for a pendulum subject to damping is given by c de + g/Lsin(0) = 0 (0) = 00; de (0) = 0 dt dt2 mL dt where 0 is the angle of the pendulum to the vertical plumb (rad), t is time(s) c is the damping factor (0.2kg – m/s), m is the mass (0.3kg), L is the length of the pendulum (Im), 0, is the initial angle from when the pendulum is released (7/6) and g is the acceleration of gravity. Determine the behavior of this pendulum until the pendulum damps consiste ntly below 0 < 1/12.
The differential equation for a pendulum subject to damping is given by c de + g/Lsin(0) = 0 (0) = 00; de (0) = 0 dt dt2 mL dt where 0 is the angle of the pendulum to the vertical plumb (rad), t is time(s) c is the damping factor (0.2kg – m/s), m is the mass (0.3kg), L is the length of the pendulum (Im), 0, is the initial angle from when the pendulum is released (7/6) and g is the acceleration of gravity. Determine the behavior of this pendulum until the pendulum damps consiste ntly below 0 < 1/12.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The differential equation for a pendulum subject to damping is given by
c de
+ g/Lsin(0) = 0 (0) = 0;
de
(0) = 0
dt
dt2
mL dt
where 0 is the angle of the pendulum to the vertical plumb (rad), t is time(s) c is the
damping factor (0.2kg – m/s), m is the mass (0.3kg), L is the length of the pendulum
(1m), 0, is the initial angle from when the pendulum is released (T/6) and g is the
acceleration of gravity. Determine the behavior of this pendulum until the pendulum
damps consiste ntly below 0 < 1/12.
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