The dissolving of Borax (sodium tetraborate) occurs via the reaction below Na2B407 10H₂O(s) <-> 2 Nat(aq) + B4072 (aq) + 10 H₂O(l) K = 0.047 @ 25°C AH° 109 kJ/mol; AS°= 340 J/mol*K If the starting concentration of B4O72-(aq) is 0.17M and the starting concentration of sodium ions is 0.34M at 25°C, which direction will the reaction proceed? O The reaction will proceed to the left O The reaction will proceed to the right O The reaction is at equilibrium

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Chapter12: Chemical Equilibrium
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Problem 12.81PAE
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The dissolving of Borax (sodium tetraborate) occurs via the reaction below
Na2B407 10H₂O(s) <-> 2 Nat(aq) + B4072 (aq) + 10 H₂O(l) K = 0.047 @
25°C
AH° = 109 kJ/mol; AS°= 340 J/mol*K
If the starting concentration of B4O72-(aq) is 0.17M and the starting
concentration of sodium ions is 0.34M at 25°C, which direction will the
reaction proceed?
The reaction will proceed to the left
O The reaction will proceed to the right
O The reaction is at equilibrium
Transcribed Image Text:The dissolving of Borax (sodium tetraborate) occurs via the reaction below Na2B407 10H₂O(s) <-> 2 Nat(aq) + B4072 (aq) + 10 H₂O(l) K = 0.047 @ 25°C AH° = 109 kJ/mol; AS°= 340 J/mol*K If the starting concentration of B4O72-(aq) is 0.17M and the starting concentration of sodium ions is 0.34M at 25°C, which direction will the reaction proceed? The reaction will proceed to the left O The reaction will proceed to the right O The reaction is at equilibrium
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