Asked Dec 17, 2019

The distance between two telephone
poles is 50.0 m. When a 1.00-kg bird
lands on the telephone wire midway
between the poles, the wire sags 0.200 m. Draw a free-body
diagram of the bird. How much tension does the bird produce
in the wire? Ignore the weight of the wire.


Expert Answer

Step 1

(a) The free body diagram is shown below


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The distance between telephone poles is 50.0 m and a bird of mass 1 kg lands on the telephone wire midway between the poles, the wire sags 0.200 m. The free body diagram of the bird is shown below. 9.80 N Figure I The gravitational force on the bird points downward and the force on the wire are the tensional forces, T1 and T 2.

Step 2

(b) Let us find th...


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Consider an inverted isosceles triangle with the base as the line joining the two poles and the bird to be at the apex. Write the expression for the angle by which the wire sags tan e = 1 Here, e is the angle by which the wire sags, z is the distance the wire sags and y is half the distance between the poles. Substitute 0.2 m for a and 0 m for y to find e. 0.2 m tan 0 50 e = 0.458° Write the expression for the net force in the vertical direction. EF, = 0 2T sin 0 – mg=0 2T sin 0 = mg


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