The distributed load is supported by a beam with a pin and a roller.Determine the reaction (magnitude and direction) on the supports (pin and roller). ♫1W₁WmaxWW₂TIF↓FF1The first one is triangular, the one below is rectangular and the distributed load at the bottom istrapezoidal.Equivalent concentrated load of triangular shape = Area of triangle = 1 WmaxEquivalent concentrated load of rectangular shape = Area of rectangle = WIEquivalent concentrated load of trapezoidal shape = Area of trapezoid = 1 (W₁ + W₂)

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Answered: The distributed load is supported by a…

The distributed load is supported by a beam with a pin and a roller. Determine the reaction (magnitude and direction) on the supports (pin and roller)

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter5: Stresses In Beams (basic Topics)

Section: Chapter Questions

Problem 5.12.12P: A flying but tress transmit s a load P = 25 kN, acting at an angle of 60º to the horizontal, to the...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

The distributed load is supported by a beam with a pin and a roller.

Determine the reaction (magnitude and direction) on the supports (pin and roller).

♫
1
W₁
Wmax
W
W₂
TI
F
↓
F
F
1
The first one is triangular, the one below is rectangular and the distributed load at the bottom is
trapezoidal.
Equivalent concentrated load of triangular shape = Area of triangle = 1 Wmax
Equivalent concentrated load of rectangular shape = Area of rectangle = WI
Equivalent concentrated load of trapezoidal shape = Area of trapezoid = 1 (W₁ + W₂)

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