The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 50.1 for a sample of size 21 and standard deviation 11.9. Estimate how much the drug will lower atypical patient' s systolic blood pressure (using a 99% confidence level Assume the data is from a normally Enter your answer as a tri-linear inequality accurate to three decimal places.

Q: Tanner is concerned about the number of prescriptions his elderly clients have. He would like to…

A: The provided information are:

Q: A federal report indicated that 27% of children ages 2 to 5 years old had a good diet – an increase…

A: The provided information are: Sample proportion p^=27%=0.27 Margin of error (E) = 2% = 0.02…

Q: According to the National Health Statistics Reports, the standard deviation of the weights of all…

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Q: A researcher collected a sample of data regarding the mean number of hours a person spends online…

A: Confidence Interval :  A confidence interval refers to the probability that a population parameter…

Q: 2. Suppose that the sample mean temperature of 31 hot air balloons (in flight) is 97° Celsius with a…

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Q: In a study of times required from room service at a newly opened Plaza Hotel, 20 deliveries had a…

A: Given, Mean, -x = 24.2 Standard deviation, s = 8.7 Sample size, n = 20 Degrees of freedom, df = n-1=…

Q: Assume that a sample is used to estimate a population mean μμ. Find the 95% confidence interval for…

A: We have given that,  Sample mean (x̄) = 69.7, standard deviation (σ) = 8.1 and sample size (n) = 362…

Q: A cell phone company claims that the average time a person spends on their phone is 12.8 hours a…

A: Given that, Population mean=μ=12.8 Hours Sample mean=X Bar=12.2 Hours Sample standard deviation= 2.3…

Q: a study of nickels showed that the standard deviation of the weight of nickels is 150 milligrams. a…

A: It is given that confidence level is 0.95, standard deviation is 150 and margin of error E is 20.

Q: A market researcher wants to evaluate car insurance savings at a competing company. Based on past…

A: Given that, A market researcher wants to evaluate car insurance savings at a competing company.…

Q: The width of a confidence interval estimate for a mean will be narrower for a sample size of 50 than…

A: The critical value of 95% confidence level will be greater than the critical value of the 90%…

Q: A social worker is concerned about the number of prescriptions her elderly clients have. She would…

A: Given: Standard deviation (σ) = 5.2 Margin of error (E) = 2 Confidence level = 99%

Q: The previous mean amount of time spent using the lab computer was 61 minutes. Find a​ 95% confidence…

A: confidence interval with outliers: sample size (n) = 12    sample mean (x̄)  =  Σx/n  = 812/12 =…

Q: A cell phone company claims that the average time a person spends on their phone is 12.8 hours a…

A: The provided information is: Sample meanx¯=12.20 Population standard deviationσ=2.30 Level of…

Q: A researcher wishes to estimate the proportion of adults who have​ high-speed Internet access. What…

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Q: To estimate the average life of their 100-watt bulbs, the manufacturer randomly samples 120 light…

A: Given Information : To estimate the average life of their 100-watt bulbs, the manufacturer randomly…

Q: sample of size 1045 with a mean of 33.5 and a standard deviation of 13.5 ri-linear inequality…

A: As the population standard deviation is not known, we will use t-distribution. Given: Xˉ=33.5…

Q: Suppose that the population standard deviation of student scores is 20. What will be the sample size…

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Q: Suppose when will like to construct a 99% confidence interval for a sample mean when the population…

A: Here we have to find the Z critical value at 99% confidence level

Q: A sample of 23 pomegranates found they had a mean weight of 12.7ounces and a standard deviation of…

A: A sample of 23 pomegranates is selected which have a mean weight of 12.7ounces and a standard…

Q: A pizza shop owner wishes to find the 99% confidence interval of the true mean cost of a large plain…

A: Given σ=0.14E=0.11n=?The z-value at 99% confidence is 2.58

Q: A development expert wants to use a one-sample z interval to estimate the proportion of women aged…

A: Given that, They take an SRS of 50 women from this population and find that 48 are literate.

Q: A country club wants to poll a random sample of its 320 members to estimate the proportion likely to…

A: Given data: Margin of error ( ME ) = 0.05 Random sample (N) = 320 Confidence level  = 99 % To find:…

Q: Assume that a sample is used to estimate a population mean μμ. Find the 99% confidence interval for…

A:

Q: An analyst is planning to estimate the mean of a quantitative variable using a 95% confidence…

A: Given that, Critical value: Using the z-table, the critical value at 95% confidence level is

Q: what is a 95% confidence interval for the average weight of all dogs if a sample of 31 dogs have an…

A: Given, Sample size = 31 Sample mean = 54 Sample standard deviation = 0.5   Since the population…

Q: A pizza shop owner wishes to find the 95% confidence interval of the true mean cost of a large plain…

A: It is given that Population SD = 0.26 Margin of error E = 0.15 Level of confidence = 0.95 The…

Q: Find a 90% confidence interval for the mean daily income this parking garage will generate and…

A: here n = 46 sample mean = 8600$ sample standard deviation  = s= 1300$ here area in both tail =( 1 -…

Q: Suppose you measure the heights of a SRS of 400 eight- year-old US girls. If their average height ()…

A: Given information Sample size n = 400 Average height = 142 cm Sample mean x̅ = 36.7 years Population…

Q: A meteorologist who sampled 13 randomly selected thunderstorms found that the average speed at which…

A: We have given that,  Sample mean (x̄) = 15.0 , standard deviation (s)= 1.7 and sample size (n) = 13…

Q: Assume that a sample is used to estimate a population mean μμ. Find the 99.5% confidence interval…

A: Solution: From the given information, n=842, sample mean is x-bar is 59.1 and the sample standard…

Q: According to a report, 65% of parents of teens aged 13 to 17 said that they had checked which web…

A: Given: Sample proportion=p=0.65. Sample size=n=1020.

Q: A researcher wishes to estimate the proportion of adults who have high speed internet access. What…

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Q: How large a sample is needed to estimate the true proportion of these children getting adequate…

A: It is given that Proportion p = 0.45 Margin of error E = 0.025 Level of confidence = 0.99 The…

Q: b. Estimate the 95% confidence interval for the standard deviation if a research of (A + 8)…

A: Confidence interval :  Confidence interval formula for the population variance is given by…

Q: Assume that a sample is used to estimate a population mean μ. Find the 80% confidence interval for a…

A:

Q: A study of 100 randomly selected students revealed that 39% of sampled student used books for…

A: p^ = 0.39 , n = 100

Q: A report in a research journal states that the average weight loss of people on a certain drug is 17…

A: the mean weight loss of people on this drug, μ, could be as low as 14 lbs.

Q: has a mean life of 480 hours, construct a 99% confidence interval for the mean of the flashlights…

A: here population standard deviation  = 35 sample size  = 150  sample mean   = 480 and Z-critical for…

Q: Suppose that Jerry (a baker) wants to find a 95% Confidence Interval for the mean baking time for…

A:

Q: Assume that a sample is used to estimate a population mean μμ. Find the 99% confidence interval for…

A: Obtain the degrees of freedom. The degrees of freedom  is obtained below:

Q: A random sample of 100 packs of aplles with a professed weight of 1 kg was found to have mean 1020g…

A: Given:  Sample size (n) = 100 Mean (x) = 1020 g  Standard deviation (s) = 12 g

Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

A:

Q: A physical exercise has a mean length of 20 minutes with a standard deviation of 5 minutes. A gym…

A: Obtain the sample size needed. The sample size needed is obtained below as follows : Procedure for…

Q: Assume that a sample is used to estimate a population mean μμ. Find the 80% confidence interval for…

A:

Q: Assume that a sample is used to estimate a population mean μμ. Find the 99% confidence interval for…

A: Given,sample size(n)=665sample mean(x¯)=53.1standard deviation(s)=8.5degrees of freedom…

Q: Enter your answer as an open-interval (i.e., parentheses) accurate to one decimal place. Confidence…

A: Reviewing information, X=(82.1, 87.1, 84.6, 81.3, 81.8, 86.1, 82.3, 86.7, 84.6)

Q: How would this confidence interval be affected if the random sample was for 16 employees? Work out…

A: It is given that sample mean is 56 and the sample standard deviation is 99.