The electric field along the z-axis is given by È = azk where a = -42 N/m.C. Find the electric potential difference between z1=1.6m and z2=3.6m; V(z2) – V(z1) =? Express your answer in units of Volts and use one decimal place. -Hint: de = îdx +ĵdy+kdz

The electric field along the z-axis is given by È = azk where a = -42 N/m.C. Find the electric potential difference between z1=1.6m and z2=3.6m; V(z2) – V(z1) =? Express your answer in units of Volts and use one decimal place. -Hint: de = îdx +ĵdy+kdz

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...

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The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104 V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?
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An electron moving parallel to the x axis has an initial speed of 3.70 106 m/s at the origin. Its speed is reduced to 1.40 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. (b) Which point is at the higher potential?
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(a) Calculate the electric potential 0.250 cm from ail electron, (b) What is the electric potential difference between two points that are 0.250 cm and 0.750 cm from an electron? (c) How would the answers change if the electron were replaced with a proton?
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A particle with charge +q is at the origin. A particle with charge 2q is at x = 2.00 m on the x axis. (a) For what finite value(s) of x is the electric field zero? (b) For what finite value(s) of x is the electric potential zero?